# The Report in SQL | HackerRank Solution

Hello coders, today we are going to solve The Report HackerRank Solution in SQL.

## Problem

You are given two tables: Students and GradesStudents contains three columns IDName and Marks.

Grades contains the following data:

Ketty gives Eve a task to generate a report containing three columns: NameGrade and MarkKetty doesn’t want the NAMES of those students who received a grade lower than 8. The report must be in descending order by grade — i.e. higher grades are entered first. If there is more than one student with the same grade (8-10) assigned to them, order those particular students by their name alphabetically. Finally, if the grade is lower than 8, use “NULL” as their name and list them by their grades in descending order. If there is more than one student with the same grade (1-7) assigned to them, order those particular students by their marks in ascending order.

Write a query to help Eve.

Sample Input

Sample Output

``````Maria 10 99
Jane 9 81
Julia 9 88
Scarlet 8 78
NULL 7 63
NULL 7 68``````

Note

Print “NULL”  as the name if the grade is less than 8.

## Explanation

Consider the following table with the grades assigned to the students:

So, the following students got 89 or 10 grades:

• Maria (grade 10)
• Jane (grade 9)
• Julia (grade 9)
• Scarlet (grade 8)

## Solution – The Report in SQL

### MySQL

```SELECT CASE
WHEN G.grade > 7 THEN S.name
ELSE NULL
end AS names,
S.marks
FROM   students S
ON S.marks BETWEEN G.min_mark AND G.max_mark
ORDER  BY G.grade DESC,
names ASC,
S.marks ASC;```

Disclaimer: The above Problem (The Report) is generated by Hacker Rank but the Solution is Provided by CodingBroz. This tutorial is only for Educational and Learning Purpose.

### 1 thought on “The Report in SQL | HackerRank Solution”

1. SELECT CASE WHEN GRADE > 7 THEN NAME ELSE NULL END,