# Ruby Array – Index, Part 2 Solution

In this post, we will solve Ruby Array – Index, Part 2 HackerRank Solution. This problem (Ruby Array – Index, Part 2) is a part of HackerRank Ruby series.

Here are some other ways to access array objects in Ruby.

To access the elements from the end of the list, we can use negative indices.

For the array,

``arr = [9, 5, 1, 2, 3, 4, 0, -1]``
`````` > arr[-1]
=> -1``````
• The first element of the array can be accessed using
`````` > arr.first
=> 9``````
• The last element of the array can be accessed using
`````` > arr.last
=> -1``````
• The first `n` elements of the array can be accessed using
`````` arr.take(3)
=> [9, 5, 1]``````
• Everything but the first `n` elements of the array can be accessed using
`````` arr.drop(3)
=> [2, 3, 4, 0, -1]``````

In this challenge, you have to use the syntax as explained above and complete the functions accordingly.

## Solution – Ruby Array – Index, Part 2

```def neg_pos(arr, index)
# return the element of the array at the position `index` from the end of the list
# Clue : arr[-index]
return arr[-index]
end

def first_element(arr)
# return the first element of the array
# arr.first
return arr.first
end

def last_element(arr)
# return the last element of the array
return arr.last
end

def first_n(arr, n)
# return the first n elements of the array
arr.take(n)
end

def drop_n(arr, n)
# drop the first n elements of the array and return the rest
arr.drop(n)
end
```

Note: This problem (Ruby Array – Index, Part 2) is generated by HackerRank but the solution is provided by CodingBroz. This tutorial is only for Educational and Learning purpose.