Pattern Syntax Checker | HackerRank Solution

Hello coders, today we are going to solve Pattern Syntax Checker HackerRank Solution in Java.

Problem

Using Regex, we can easily match or search for patterns in a text. Before searching for a pattern, we have to specify one using some well-defined syntax.

In this problem, you are given a pattern. You have to check whether the syntax of the given pattern is valid.

Note: In this problem, a regex is only valid if you can compile it using the Pattern.compile method.

Input Format

The first line of input contains an integer N, denoting the number of test cases. The next N lines contain a string of any printable characters representing the pattern of a regex.

Output Format

For each test case, print Valid if the syntax of the given pattern is correct. Otherwise, print Invalid. Do not print the quotes.

Sample Input

 3
 ([A-Z])(.+)
 [AZ[a-z](a-z)
 batcatpat(nat

Sample Output

 Valid
 Invalid
 Invalid

Solution – Pattern Syntax Checker in Java

import java.util.Scanner;
import java.util.regex.*;

public class Solution
{
   public static void main(String[] args){
      Scanner in = new Scanner(System.in);
        int testCases = Integer.parseInt(in.nextLine());
    
        while(testCases>0){
            String pattern = in.nextLine();

            try {
                Pattern.compile(pattern);
                System.out.println("Valid");
            } catch(PatternSyntaxException e) {
                System.out.println("Invalid");
            }

            testCases--;
        }
   }
}

Disclaimer: The above Problem ( Pattern Syntax Checker ) is generated by Hacker Rank but the Solution is Provided by CodingBroz. This tutorial is only for Educational and Learning Purpose.