# Java Loops I | HackerRank Solution

Hello coders, today we are going to solve Java Loops I HackerRank Solution.

Contents

## Problem

In this challenge, we’re going to use loops to help us do some simple math.

Given an integer, N, print its first 10 multiples. Each multiple N X i (where 1<=i<=10) should be printed on a new line in the form: N x i = result.

## Input Format

A single integer, N.

2 <= N <= 20 .

## Output Format

Print 10 lines of output; each line i (where 1 <= i <= 10) contains the result of N X i in the form:
N x i = result.

Sample input

`` 2``

Sample output

`````` 2 x 1 = 2
2 x 2 = 4
2 x 3 = 6
2 x 4 = 8
2 x 5 = 10
2 x 6 = 12
2 x 7 = 14
2 x 8 = 16
2 x 9 = 18
2 x 10 = 20``````

## Solution –Java Loops 1

```import java.io.*;
import java.math.*;
import java.security.*;
import java.text.*;
import java.util.*;
import java.util.concurrent.*;
import java.util.regex.*;

public class Solution {

private static final Scanner scanner = new Scanner(System.in);
public static void main(String[] args) {
int N = scanner.nextInt();
scanner.skip("(\r\n|[\n\r\u2028\u2029\u0085])?");
if(N>1 && N<=20)
{
for(int i=1 ; i<=10 ; i++)
{
int mul=N*i;
System.out.println(N+" x "+i+" = "+mul);
}
}
scanner.close();
}
}
```

Disclaimer: The above Problem ( Java Loops 1 ) is generated by Hacker Rank but the Solution is Provided by CodingBroz. This tutorial is only for Educational and Learning Purpose.