Day 2: More Dice | 10 Days Of Statistics | HackerRank Solution

Hello coders, today we are going to solve Day 2: More Dice HackerRank Solution which is a Part of 10 Days of Statistics Series.

Day 2: More Dice



In this challenge, we practice calculating probability.


In a single toss of 2 fair (evenly-weighted) six-sided dice, find the probability that the values rolled by each die will be different and the two dice have a sum of 6.

Solution – More Dice Solution


dice1 = [1,2,3,4,5,6]
dice2 = [1,2,3,4,5,6]
total = len(dice1) * len(dice2)
total_possibilities = 0

# Verify possibilities
for i in range(len(dice1)):
    for j in range(len(dice2)):
        if dice1[i] != dice1[j] and (dice1[i] + dice1[j]) == 6:
            total_possibilities = total_possibilities + 1
            print("{0} + {1} = {2}".format(dice1[i], dice2[j], (dice1[j] + dice1[i])))

# Get probability
probability = total_possibilities / total
print("Probability: {0}/{1} = {2}".format(total_possibilities,total,probability))

The Correct answer is 1/9.

Disclaimer: The above Problem (More Dice) is generated by Hacker Rank but the Solution is Provided by CodingBroz. This tutorial is only for Educational and Learning Purpose.

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