Hello coders, today we are going to solve **Day 2: More Dice HackerRank Solution** which is a Part of** 10 Days of Statistics** Series.

**Objective**

In this challenge, we practice calculating probability.

**Task**

In a single toss of **2** fair (evenly-weighted) six-sided dice, find the probability that the values rolled by each die will be *different* and the two dice have a sum of **6**.

**Solution – More Dice Solution**

**Python**

dice1 = [1,2,3,4,5,6] dice2 = [1,2,3,4,5,6] total = len(dice1) * len(dice2) total_possibilities = 0 # Verify possibilities for i in range(len(dice1)): for j in range(len(dice2)): if dice1[i] != dice1[j] and (dice1[i] + dice1[j]) == 6: total_possibilities = total_possibilities + 1 print("{0} + {1} = {2}".format(dice1[i], dice2[j], (dice1[j] + dice1[i]))) # Get probability probability = total_possibilities / total print("Probability: {0}/{1} = {2}".format(total_possibilities,total,probability))

The **Correct **answer is **1/9**.

**Disclaimer:** The above Problem **(More Dice)** is generated by **Hacker Rank** but the Solution is Provided by CodingBroz. This tutorial is only for **Educational** and **Learning** Purpose.