In this post, we will learn how to print numbers divisible by 3 and 5 using the C++ Programming language.
The below program asks the user to enter a number. Then, this program will print all the numbers divisible by 3 and 5 lying in that particular range.
So, without further ado, let’s begin this tutorial.
C++ Program to Print Numbers Divisible by 3 and 5
// C++ Program to Print Numbers Divisible by 3 and 5
#include <iostream>
using namespace std;
int main(){
int i, n;
// Asking for input
cout << "Enter a number: ";
cin >> n;
// Displaying numbers divisible by 3 and 5
cout << "Numbers divisible by 3 and 5 are: " << endl;
for (i = 1; i <= n; i++){
if (i % 3 == 0 && i % 5 == 0){
cout << i << endl;
}
}
return 0;
}
Output
Enter a number: 75
Numbers divisible by 3 and 5 are:
15
30
45
60
75
How Does This Program Work?
int i, n;
In this program, we have declared two integer data type variables named i and n.
// Asking for input
cout << "Enter a number: ";
cin >> n;
Then, the user is asked to enter a number. The entered value gets stored in the n named variable.
// Displaying numbers divisible by 3 and 5
cout << "Numbers divisible by 3 and 5 are: " << endl;
for (i = 1; i <= n; i++){
if (i % 3 == 0 && i % 5 == 0){
cout << i << endl;
}
}
Now, we use a for loop to check whether the iterations of i are divisible by both 3 and 5.
If any iteration of i is divisible by both 3 and 5, then we print the value of that particular iteration. This loop keeps on executing until i <= n.
This gives us all the numbers divisible by 3 and 5 lying between 0 to the entered number.
Conclusion
I hope after reading this post, you understand how to print numbers divisible by 3 and 5 using the C++ Programming language.
If you have any doubt regarding the program, then contact us in the comment section. We will be delighted to assist you.
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