Alice and Bob each created one problem for HackerRank. A reviewer rates the two challenges, awarding points on a scale from 1 to 100 for three categories: problem clarity, originality, and difficulty.
The rating for Alice’s challenge is the triplet a = (a, a, a), and the rating for Bob’s challenge is the triplet b = (b, b, b).
The task is to find their comparison points by comparing a with b, a with b, and a with b.
If a[i] > b[i], then Alice is awarded 1 point. If a[i] < b[i], then Bob is awarded 1 point. If a[i] = b[i], then neither person receives a point.
Comparison points is the total points a person earned.
Given a and b, determine their respective comparison points.
a = [1, 2, 3]
b = [3, 2, 1]
For elements *0*, Bob is awarded a point because a . For the equal elements a and b, no points are earned. Finally, for elements 2, a > b so Alice receives a point.
The return array is [1, 1] with Alice’s score first and Bob’s second.
Complete the function compareTriplets in the editor below.
compareTriplets has the following parameter(s):
int a: Alice's challenge rating int b: Bob's challenge rating
int: Alice's score is in the first position, and Bob's score is in the second.
The first line contains 3 space-separated integers, a, a, and a, the respective values in triplet a.
The second line contains 3 space-separated integers, b, b, and b, the respective values in triplet b.
1 ≤ a[i] ≤ 100 1 ≤ b[i] ≤ 100
Sample Input 0
5 6 7
3 6 10
Sample Output 0
a = (5,6,7)
b = (3,6,10)
Now, let’s compare each individual score :
a > b, so Alice receives 1 point.
a = b, so nobody receives a point.
a < b, so Bob receives 1 point.
Alice’s comparison score is 1, and Bob’s comparison score is 1. Thus, we return the array [1,1].
Sample Input 1
17 28 30 99 16 8
Sample Output 1
Comparing the 0th elements, 17 < 99 so Bob receives a point.
Comparing the 1st and 2nd elements, 28>16 and 30>8 so Alice receives two points.
The return array is [2,1].
Solution in Python
#!/bin/python3 import math import os import random import re import sys # Complete the compareTriplets function below. def compareTriplets(a, b): pointa=0 pointb=0 ar =  for i in range(3): if a[i]>b[i]: pointa+=1 if a[i]<b[i]: pointb+=1 ar.insert(0,pointa) ar.insert(1,pointb) return(ar) if __name__ == '__main__': fptr = open(os.environ['OUTPUT_PATH'], 'w') a = list(map(int, input().rstrip().split())) b = list(map(int, input().rstrip().split())) result = compareTriplets(a, b) fptr.write(' '.join(map(str, result))) fptr.write('\n') fptr.close()