Write a Function in Python | HackerRank Solution

Hey coders, today we will be solving Write a Function Hacker Rank Solution in Python.

Write a Function in Python - Hacker Rank Solution



An extra day is added to the calendar almost every four years as February 29, and the day is called a leap day. It corrects the calendar for the fact that our planet takes approximately 365.25 days to orbit the sun. A leap year contains a leap day.

In the Gregorian calendar, three conditions are used to identify leap years:

  • The year can be evenly divided by 4, is a leap year, unless:
  • The year can be evenly divided by 100, it is NOT a leap year, unless:
  • The year is also evenly divisible by 400. Then it is a leap year.

This means that in the Gregorian calendar, the years 2000 and 2400 are leap years, while 1800, 1900, 2100, 2200, 2300 and 2500 are NOT leap years. 


Given a year, determine whether it is a leap year. If it is a leap year, return the Boolean True, otherwise return False.

Note that the code stub provided reads from STDIN and passes arguments to the is_leap function. It is only necessary to complete the is_leap function.

Input Format

Read year, the year to test.


1900 <= year <= 10^5

Output Format

The function must return a Boolean value (True/False). Output is handled by the provided code stub.

Sample Input 0


Sample Output 0


Explanation 0

1990 is not a multiple of 4 hence it’s not a leap year.

Solution – Write a Function in Python – Hacker Rank Solution

def is_leap(year):
    leap = False
    # Write your logic here
    if (year % 400 == 0):
        return True
    if (year % 100 == 0):
        return leap
    if (year % 4 == 0):
        return True
        return False  
    return leap

year = int(input())

Disclaimer: The above Problem (Write a Function) is generated by Hacker Rank but the Solution is provided by CodingBroz. This tutorial is only for Educational and Learning Purposes.

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