Hey coders, today we will be solving Write a Function Hacker Rank Solution in Python.
An extra day is added to the calendar almost every four years as February 29, and the day is called a leap day. It corrects the calendar for the fact that our planet takes approximately 365.25 days to orbit the sun. A leap year contains a leap day.
In the Gregorian calendar, three conditions are used to identify leap years:
- The year can be evenly divided by 4, is a leap year, unless:
- The year can be evenly divided by 100, it is NOT a leap year, unless:
- The year is also evenly divisible by 400. Then it is a leap year.
This means that in the Gregorian calendar, the years 2000 and 2400 are leap years, while 1800, 1900, 2100, 2200, 2300 and 2500 are NOT leap years.
Given a year, determine whether it is a leap year. If it is a leap year, return the Boolean True, otherwise return False.
Note that the code stub provided reads from STDIN and passes arguments to the is_leap function. It is only necessary to complete the is_leap function.
Read year, the year to test.
1900 <= year <= 10^5
The function must return a Boolean value (True/False). Output is handled by the provided code stub.
Sample Input 0
Sample Output 0
1990 is not a multiple of 4 hence it’s not a leap year.
Solution – Write a Function in Python – Hacker Rank Solution
def is_leap(year): leap = False # Write your logic here if (year % 400 == 0): return True if (year % 100 == 0): return leap if (year % 4 == 0): return True else: return False return leap year = int(input()) print(is_leap(year))