Hey coders, today we will be solving **Write a Function Hacker Rank Solution in Python**.

**Problem**

An extra day is added to the calendar almost every four years as February 29, and the day is called a leap day. It corrects the calendar for the fact that our planet takes approximately 365.25 days to orbit the sun. A leap year contains a leap day.

In the Gregorian calendar, three conditions are used to identify leap years:

- The year can be evenly divided by 4, is a leap year, unless:
- The year can be evenly divided by 100, it is NOT a leap year, unless:
- The year is also evenly divisible by 400. Then it is a leap year.

This means that in the Gregorian calendar, the years 2000 and 2400 are leap years, while 1800, 1900, 2100, 2200, 2300 and 2500 are NOT leap years.

**Task**

Given a year, determine whether it is a leap year. If it is a leap year, return the Boolean True, otherwise return False.

Note that the code stub provided reads from STDIN and passes arguments to the is_leap function. It is only necessary to complete the is_leap function.

**Input Format**

Read ** year**, the year to test.

**Constraints**

**1900 <= year <= 10^5**

**Output Format**

The function must return a Boolean value (True/False). Output is handled by the provided code stub.

**Sample Input 0**

`1990`

**Sample Output 0**

`False`

**Explanation 0**

1990 is not a multiple of 4 hence it’s not a leap year.

**Solution – Write a Function in Python – Hacker Rank Solution**

def is_leap(year): leap = False # Write your logic here if (year % 400 == 0): return True if (year % 100 == 0): return leap if (year % 4 == 0): return True else: return False return leap year = int(input()) print(is_leap(year))

**Disclaimer:** The above Problem **(Write a Function)** is generated by **Hacker Rank** but the Solution is provided by **CodingBroz**. This tutorial is only for **Educational** and **Learning** Purposes.

vaibhavWhat is leap = false in this code? And why have you returned leap in the second conditional?

Please help in knowing this, I’m new to coding.

Sweety Singhdef leap_year(year):

if(year%4==0 and year%400==0 ):

print(“leap year”)

else:

print(“not”)

year=int(input())

print(leap_year(year))

UAleap value assigned to “false” by default (before checking the given year).

So in this case returning “false” or leap in the second conditional doesn’t make any difference.

I understand the intention of the code block as it fullfils the exact requirement of the given task, but the check for the leap year could be following:

def is_leap(year):

leap = False

if (year % 400 == 0):

return True

else:

return False

return leap

year = int(input())

print(is_leap(year))

harishFor this problem we can also use simple if statement in it.

def is_leap(year):

if (year % 400 == 0):

return True

elif (year % 100 == 0):

return leap

elif (year % 4 == 0):

return True

return False

year = int(input())

print(is_leap(year))

sarathdef is_leap(year):

leap = False

# Write your logic here

if year%4==0:

if year%100==0:

if year%400==0:

return True

else:

return leap

else:

return True

else:

return leap

year = int(input())

print(is_leap(year))