Hey coders, today we will be solving Write a Function Hacker Rank Solution in Python.
Problem
An extra day is added to the calendar almost every four years as February 29, and the day is called a leap day. It corrects the calendar for the fact that our planet takes approximately 365.25 days to orbit the sun. A leap year contains a leap day.
In the Gregorian calendar, three conditions are used to identify leap years:
- The year can be evenly divided by 4, is a leap year, unless:
- The year can be evenly divided by 100, it is NOT a leap year, unless:
- The year is also evenly divisible by 400. Then it is a leap year.
This means that in the Gregorian calendar, the years 2000 and 2400 are leap years, while 1800, 1900, 2100, 2200, 2300 and 2500 are NOT leap years.
Task
Given a year, determine whether it is a leap year. If it is a leap year, return the Boolean True, otherwise return False.
Note that the code stub provided reads from STDIN and passes arguments to the is_leap function. It is only necessary to complete the is_leap function.
Input Format
Read year, the year to test.
Constraints
1900 <= year <= 10^5
Output Format
The function must return a Boolean value (True/False). Output is handled by the provided code stub.
Sample Input 0
1990Sample Output 0
FalseExplanation 0
1990 is not a multiple of 4 hence it’s not a leap year.
Solution – Write a Function in Python – Hacker Rank Solution
def is_leap(year):
leap = False
# Write your logic here
if (year % 400 == 0):
return True
if (year % 100 == 0):
return leap
if (year % 4 == 0):
return True
else:
return False
return leap
year = int(input())
print(is_leap(year))
Disclaimer: The above Problem (Write a Function) is generated by Hacker Rank but the Solution is provided by CodingBroz. This tutorial is only for Educational and Learning Purposes.
What is leap = false in this code? And why have you returned leap in the second conditional?
Please help in knowing this, I’m new to coding.
def leap_year(year):
if(year%4==0 and year%400==0 ):
print(“leap year”)
else:
print(“not”)
year=int(input())
print(leap_year(year))
leap value assigned to “false” by default (before checking the given year).
So in this case returning “false” or leap in the second conditional doesn’t make any difference.
I understand the intention of the code block as it fullfils the exact requirement of the given task, but the check for the leap year could be following:
def is_leap(year):
leap = False
if (year % 400 == 0):
return True
else:
return False
return leap
year = int(input())
print(is_leap(year))
For this problem we can also use simple if statement in it.
def is_leap(year):
if (year % 400 == 0):
return True
elif (year % 100 == 0):
return leap
elif (year % 4 == 0):
return True
return False
year = int(input())
print(is_leap(year))
def is_leap(year):
leap = False
# Write your logic here
if year%4==0:
if year%100==0:
if year%400==0:
return True
else:
return leap
else:
return True
else:
return leap
year = int(input())
print(is_leap(year))