{"id":1141,"date":"2021-04-18T14:58:08","date_gmt":"2021-04-18T09:28:08","guid":{"rendered":"https:\/\/www.codingbroz.com\/?p=1141"},"modified":"2021-06-21T17:49:40","modified_gmt":"2021-06-21T12:19:40","slug":"merge-the-tools-in-python-hackerrank-solution","status":"publish","type":"post","link":"https:\/\/www.codingbroz.com\/merge-the-tools-in-python-hackerrank-solution\/","title":{"rendered":"Merge The Tools in Python | HackerRank Solution"},"content":{"rendered":"\n<p>Hello coders, today we will be solving <strong>Merge The Tools in Python Hacker Rank Solution<\/strong>.<\/p>\n\n\n\n<figure class=\"wp-block-image size-large\"><img fetchpriority=\"high\" decoding=\"async\" width=\"1200\" height=\"675\" src=\"https:\/\/www.codingbroz.com\/wp-content\/uploads\/2021\/04\/merge-the-game-hackerrank-solution-codingbroz.png\" alt=\"Merge The Tools in Python\" class=\"wp-image-1143\" srcset=\"https:\/\/www.codingbroz.com\/wp-content\/uploads\/2021\/04\/merge-the-game-hackerrank-solution-codingbroz.png 1200w, https:\/\/www.codingbroz.com\/wp-content\/uploads\/2021\/04\/merge-the-game-hackerrank-solution-codingbroz-768x432.png 768w\" sizes=\"(max-width: 1200px) 100vw, 1200px\" \/><\/figure>\n\n\n\n<div id=\"ez-toc-container\" class=\"ez-toc-v2_0_65 ez-toc-wrap-left counter-hierarchy ez-toc-counter ez-toc-custom ez-toc-container-direction\">\n<label for=\"ez-toc-cssicon-toggle-item-6636735d89fd6\" class=\"ez-toc-cssicon-toggle-label\"><label class=\"ez-toc-title\">Table of Contents<\/label>\n<span class=\"ez-toc-cssicon\"><span class=\"eztoc-hide\" style=\"display:none;\">Toggle<\/span><span class=\"ez-toc-icon-toggle-span\"><svg style=\"fill: #0090ff;color:#0090ff\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" class=\"list-377408\" width=\"20px\" height=\"20px\" viewBox=\"0 0 24 24\" fill=\"none\"><path d=\"M6 6H4v2h2V6zm14 0H8v2h12V6zM4 11h2v2H4v-2zm16 0H8v2h12v-2zM4 16h2v2H4v-2zm16 0H8v2h12v-2z\" fill=\"currentColor\"><\/path><\/svg><svg style=\"fill: #0090ff;color:#0090ff\" class=\"arrow-unsorted-368013\" xmlns=\"http:\/\/www.w3.org\/2000\/svg\" width=\"10px\" height=\"10px\" viewBox=\"0 0 24 24\" version=\"1.2\" baseProfile=\"tiny\"><path d=\"M18.2 9.3l-6.2-6.3-6.2 6.3c-.2.2-.3.4-.3.7s.1.5.3.7c.2.2.4.3.7.3h11c.3 0 .5-.1.7-.3.2-.2.3-.5.3-.7s-.1-.5-.3-.7zM5.8 14.7l6.2 6.3 6.2-6.3c.2-.2.3-.5.3-.7s-.1-.5-.3-.7c-.2-.2-.4-.3-.7-.3h-11c-.3 0-.5.1-.7.3-.2.2-.3.5-.3.7s.1.5.3.7z\"\/><\/svg><\/span><\/span><\/label><input type=\"checkbox\"  id=\"ez-toc-cssicon-toggle-item-6636735d89fd6\" checked \/><nav><ul class='ez-toc-list ez-toc-list-level-1 ' ><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-1\" href=\"https:\/\/www.codingbroz.com\/merge-the-tools-in-python-hackerrank-solution\/#Problem\" title=\"Problem\">Problem<\/a><ul class='ez-toc-list-level-3' ><li class='ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-2\" href=\"https:\/\/www.codingbroz.com\/merge-the-tools-in-python-hackerrank-solution\/#Function_Description\" title=\"Function Description&nbsp;\">Function Description&nbsp;<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-3'><a class=\"ez-toc-link ez-toc-heading-3\" href=\"https:\/\/www.codingbroz.com\/merge-the-tools-in-python-hackerrank-solution\/#Prints\" title=\"Prints\">Prints<\/a><\/li><\/ul><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-4\" href=\"https:\/\/www.codingbroz.com\/merge-the-tools-in-python-hackerrank-solution\/#Input_Format\" title=\"Input Format\">Input Format<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-5\" href=\"https:\/\/www.codingbroz.com\/merge-the-tools-in-python-hackerrank-solution\/#Constraints\" title=\"Constraints\">Constraints<\/a><\/li><li class='ez-toc-page-1 ez-toc-heading-level-2'><a class=\"ez-toc-link ez-toc-heading-6\" href=\"https:\/\/www.codingbroz.com\/merge-the-tools-in-python-hackerrank-solution\/#Solution_%E2%80%93_Merge_The_Tools_in_Python_%E2%80%93_Hacker_Rank_Solution\" title=\"Solution &#8211; Merge The Tools in Python &#8211; Hacker Rank Solution\">Solution &#8211; Merge The Tools in Python &#8211; Hacker Rank Solution<\/a><\/li><\/ul><\/nav><\/div>\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Problem\"><\/span><strong>Problem<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h2>\n\n\n\n<p>Consider the following:<\/p>\n\n\n\n<p>A string,&nbsp;<strong><em>s<\/em><\/strong>, of length&nbsp;<strong><em>n<\/em><\/strong>&nbsp;where&nbsp;<strong>s = c0c1. . . . cn-1<\/strong>.<\/p>\n\n\n\n<p>An integer,&nbsp;<strong><em>k<\/em><\/strong>, where&nbsp;<strong><em>k<\/em><\/strong>&nbsp;is a factor of&nbsp;<strong><em>n<\/em><\/strong>.<\/p>\n\n\n\n<p>We can split&nbsp;<strong><em>s<\/em><\/strong>&nbsp;into&nbsp;<strong>n\/k<\/strong>&nbsp;substrings where each subtring,&nbsp;<strong>ti<\/strong>, consists of a contiguous block of&nbsp;<strong><em>k<\/em><\/strong>&nbsp;characters in&nbsp;<em><strong>s<\/strong><\/em>. Then, use each&nbsp;<strong><em>ti<\/em><\/strong>&nbsp;to create string&nbsp;<strong><em>ui<\/em><\/strong>&nbsp;such that:<\/p>\n\n\n\n<p>The characters in&nbsp;<strong><em>ui<\/em><\/strong>&nbsp;are a subsequence of the characters in&nbsp;<strong><em>ti<\/em><\/strong>.<\/p>\n\n\n\n<p>Any repeat occurrence of a character is removed from the string such that each character in&nbsp;<strong><em>ui<\/em><\/strong>&nbsp;occurs exactly once. In other words, if the character at some index&nbsp;<strong><em>j<\/em><\/strong>&nbsp;in&nbsp;<strong><em>ti<\/em><\/strong>&nbsp;occurs at a previous index&nbsp;<strong>&lt;<\/strong>&nbsp;<strong><em>j<\/em><\/strong>&nbsp;in&nbsp;<em><strong>ti<\/strong><\/em>, then do not include the character in string&nbsp;<em><strong>ui<\/strong><\/em>.<\/p>\n\n\n\n<p>Given&nbsp;<strong><em>s<\/em><\/strong>&nbsp;and&nbsp;<strong><em>k<\/em><\/strong>, print&nbsp;<strong>n\/k<\/strong>&nbsp;lines where each line&nbsp;<strong><em>i<\/em><\/strong>&nbsp;denotes string&nbsp;<strong><em>ui<\/em><\/strong>.<\/p>\n\n\n\n<p><strong>Example<\/strong><\/p>\n\n\n\n<p><strong><em>s<\/em>&nbsp;= &#8220;AAABCADDE&#8221;<\/strong><\/p>\n\n\n\n<p><strong><em>k<\/em>&nbsp;= 3<\/strong><\/p>\n\n\n\n<p>There are three substrings of length&nbsp;<strong>3<\/strong>&nbsp;to consider: &#8216;AAA&#8217;, &#8216;BCA&#8217; and &#8216;DDE&#8217;. The first substring is all &#8216;A&#8217; characters, so&nbsp;<strong>u1 = &#8216;A&#8217;<\/strong>. The second substring has all distinct characters, so&nbsp;<strong><em>u2&nbsp;<\/em>= &#8216;BCA&#8217;<\/strong>. The third substring has&nbsp;<strong>2<\/strong>&nbsp;different characters, so&nbsp;<strong>u3 = &#8216;DE&#8217;<\/strong>. Note that a subsequence maintains the original order of characters encountered. The order of characters in each subsequence shown is important.<\/p>\n\n\n\n<h3 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Function_Description\"><\/span><strong>Function Description&nbsp;<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n\n\n\n<p>Complete the merge_the_tools function in the editor below.<\/p>\n\n\n\n<p>merge_the_tools has the following parameters:<\/p>\n\n\n\n<ul><li>string s: the string to analyze<\/li><li>int k: the size of substrings to analyze<\/li><\/ul>\n\n\n\n<h3 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Prints\"><\/span><strong>Prints<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h3>\n\n\n\n<p>Print each subsequence on a new line. There will be&nbsp;<strong>n\/k<\/strong>&nbsp;of them. No return value is expected.<\/p>\n\n\n\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Input_Format\"><\/span><strong>Input Format<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h2>\n\n\n\n<p>The first line contains a single string,&nbsp;<strong><em>s<\/em><\/strong>.<\/p>\n\n\n\n<p>The second line contains an integer,&nbsp;<strong><em>k<\/em><\/strong>, the length of each substring.<\/p>\n\n\n\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Constraints\"><\/span><strong>Constraints<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h2>\n\n\n\n<ul><li><strong>1 &lt;= n &lt;= 10^4,&nbsp;<\/strong>where&nbsp;<strong>n<\/strong>&nbsp;is the length of&nbsp;<strong>s<\/strong><\/li><li><strong>1 &lt;= k &lt;= n&nbsp;<\/strong><\/li><li>It is guaranteed that&nbsp;<strong>n<\/strong>&nbsp;is a multiple of&nbsp;<strong><em>k<\/em><\/strong>.<\/li><\/ul>\n\n\n\n<p><strong>Sample Input<\/strong><\/p>\n\n\n\n<pre class=\"wp-block-preformatted\">STDIN       Function\n-----       --------\nAABCAAADA   s = 'AABCAAADA'\n3           k = 3<\/pre>\n\n\n\n<p><strong>Sample Output&nbsp;<\/strong><\/p>\n\n\n\n<pre class=\"wp-block-preformatted\">AB\nCA\nAD<\/pre>\n\n\n\n<p><strong>Explanation&nbsp;<\/strong><\/p>\n\n\n\n<p>Split&nbsp;<strong>s<\/strong>&nbsp;into&nbsp;<strong>n\/k = 9\/3 = 3<\/strong>&nbsp;equal parts of length&nbsp;<strong><em>k<\/em>&nbsp;= 3<\/strong>. Convert each&nbsp;<em><strong>ti<\/strong><\/em>&nbsp;to&nbsp;<em><strong>ui<\/strong><\/em>&nbsp;by removing any subsequent occurrences of non-distinct characters in&nbsp;<strong><em>ti<\/em><\/strong>:<\/p>\n\n\n\n<ol><li><strong>t0 = &#8220;AAB&#8221; &#8211; u0 = &#8220;AB&#8221;<\/strong><\/li><li><strong>t1 = &#8220;CAA&#8221; &#8211; u1 = &#8220;CA&#8221;<\/strong><\/li><li><strong>t2 = &#8220;ADA&#8221; &#8211; u2 = &#8220;AD&#8221;<\/strong><\/li><\/ol>\n\n\n\n<p>Print each&nbsp;<strong><em>ui<\/em><\/strong>&nbsp;on a new line.<\/p>\n\n\n\n<h2 class=\"wp-block-heading\"><span class=\"ez-toc-section\" id=\"Solution_%E2%80%93_Merge_The_Tools_in_Python_%E2%80%93_Hacker_Rank_Solution\"><\/span><strong>Solution &#8211; Merge The Tools in Python &#8211; Hacker Rank Solution<\/strong><span class=\"ez-toc-section-end\"><\/span><\/h2>\n\n\n\n<pre class=\"EnlighterJSRAW\" data-enlighter-language=\"python\" data-enlighter-theme=\"\" data-enlighter-highlight=\"\" data-enlighter-linenumbers=\"\" data-enlighter-lineoffset=\"\" data-enlighter-title=\"\" data-enlighter-group=\"\">def merge_the_tools(string, k):\n    # your code goes here\n    temp = []\n    len_temp = 0\n    for item in string:\n        len_temp += 1\n        if item not in temp:\n            temp.append(item)\n        if len_temp == k:\n            print (''.join(temp))\n            temp = []\n            len_temp = 0\nif __name__ == '__main__':\n    string, k = input(), int(input())\n    merge_the_tools(string, k)<\/pre>\n\n\n\n<script async src=\"https:\/\/pagead2.googlesyndication.com\/pagead\/js\/adsbygoogle.js\"><\/script>\n<ins class=\"adsbygoogle\"\n     style=\"display:block; text-align:center;\"\n     data-ad-layout=\"in-article\"\n     data-ad-format=\"fluid\"\n     data-ad-client=\"ca-pub-5246141430412355\"\n     data-ad-slot=\"8798433565\"><\/ins>\n<script>\n     (adsbygoogle = window.adsbygoogle || []).push({});\n<\/script>\n\n\n\n<p><strong>Disclaimer:<\/strong> The above Problem <strong>(<a href=\"https:\/\/www.hackerrank.com\/challenges\/merge-the-tools\/problem\" target=\"_blank\" aria-label=\"Merge The Tools (opens in a new tab)\" rel=\"noreferrer noopener\" class=\"rank-math-link\">Merge The Tools<\/a>)<\/strong> is generated by <strong>Hacker Rank<\/strong> but the Solution is generated by <strong>CodingBroz<\/strong>. This tutorial is only for <strong>Educational<\/strong> and <strong>Learning<\/strong> purpose.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>Hello coders, today we will be solving Merge The Tools in Python Hacker Rank Solution. Problem Consider the following: A string,&nbsp;s, of length&nbsp;n&nbsp;where&nbsp;s = c0c1. . . . cn-1. An integer,&nbsp;k, where&nbsp;k&nbsp;is a factor of&nbsp;n. We can split&nbsp;s&nbsp;into&nbsp;n\/k&nbsp;substrings where each subtring,&nbsp;ti, consists of a contiguous block of&nbsp;k&nbsp;characters in&nbsp;s. Then, use each&nbsp;ti&nbsp;to create string&nbsp;ui&nbsp;such that: The [&hellip;]<\/p>\n","protected":false},"author":1,"featured_media":1143,"comment_status":"open","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"site-sidebar-layout":"default","site-content-layout":"default","ast-site-content-layout":"","site-content-style":"default","site-sidebar-style":"default","ast-global-header-display":"","ast-banner-title-visibility":"","ast-main-header-display":"","ast-hfb-above-header-display":"","ast-hfb-below-header-display":"","ast-hfb-mobile-header-display":"","site-post-title":"","ast-breadcrumbs-content":"","ast-featured-img":"","footer-sml-layout":"","theme-transparent-header-meta":"default","adv-header-id-meta":"","stick-header-meta":"","header-above-stick-meta":"","header-main-stick-meta":"","header-below-stick-meta":"","astra-migrate-meta-layouts":"default","ast-page-background-enabled":"default","ast-page-background-meta":{"desktop":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-gradient":""},"tablet":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-gradient":""},"mobile":{"background-color":"","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-gradient":""}},"ast-content-background-meta":{"desktop":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-gradient":""},"tablet":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-gradient":""},"mobile":{"background-color":"var(--ast-global-color-5)","background-image":"","background-repeat":"repeat","background-position":"center center","background-size":"auto","background-attachment":"scroll","background-type":"","background-media":"","overlay-type":"","overlay-color":"","overlay-gradient":""}},"_jetpack_memberships_contains_paid_content":false,"footnotes":""},"categories":[9,107],"tags":[55,137,56,109],"jetpack_sharing_enabled":true,"jetpack_featured_media_url":"https:\/\/www.codingbroz.com\/wp-content\/uploads\/2021\/04\/merge-the-game-hackerrank-solution-codingbroz.png","jetpack-related-posts":[],"_links":{"self":[{"href":"https:\/\/www.codingbroz.com\/wp-json\/wp\/v2\/posts\/1141"}],"collection":[{"href":"https:\/\/www.codingbroz.com\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.codingbroz.com\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.codingbroz.com\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.codingbroz.com\/wp-json\/wp\/v2\/comments?post=1141"}],"version-history":[{"count":4,"href":"https:\/\/www.codingbroz.com\/wp-json\/wp\/v2\/posts\/1141\/revisions"}],"predecessor-version":[{"id":3620,"href":"https:\/\/www.codingbroz.com\/wp-json\/wp\/v2\/posts\/1141\/revisions\/3620"}],"wp:featuredmedia":[{"embeddable":true,"href":"https:\/\/www.codingbroz.com\/wp-json\/wp\/v2\/media\/1143"}],"wp:attachment":[{"href":"https:\/\/www.codingbroz.com\/wp-json\/wp\/v2\/media?parent=1141"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.codingbroz.com\/wp-json\/wp\/v2\/categories?post=1141"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.codingbroz.com\/wp-json\/wp\/v2\/tags?post=1141"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}