# Which Mixture | CodeChef Solution

Hello coders, today we are going to solve Which Mixture CodeChef Solution whose Problem Code is MIXTURE.

Chef has A units of solid and B units of liquid. He combines them to create a mixture. What kind of mixture does Chef produce: a solution, a solid, or a liquid?

A mixture is called a:

1. A solution if A > 0 and B > 0,
2. A solid if B = 0, or
3. A liquid if A = 0.

## Input Format

• The first line contains T denoting the number of test cases. Then the test cases follow.
• Each test case contains two space-separated integers A and B on a single line.

## Output Format

For each test case, output on a single line the type of mixture Chef produces, whether it is a Solution, Solid, or Liquid. The output is case sensitive.

## Constraints

• 1 â‰¤ T â‰¤ 20
• 0 â‰¤ A, B â‰¤ 100
• A +B > 0

Subtask 1 (100 points): Original constraints

Sample Input 1

``````3
10 5
0 3
3 0
``````

Sample Output 1

``````Solution
Liquid
Solid
``````

Explanation

Test case 1: Chef adds both solid and liquid to the mixture, hence the mixture is a solution.
Test case 2: Chef does not add solid to the mixture, hence the mixture is liquid.
Test case 3: Chef does not add liquid to the mixture, hence the mixture is solid.

## Solution – Which Mixture

### C++

```#include <iostream>
using namespace std;

int main() {
int test;
cin >> test;

while (test--){
int a, b;
cin >> a >> b;
if (a == 0){
cout << "Liquid" << endl;
}
else if (b == 0){
cout << "Solid" << endl;
}
else{
cout << "Solution" << endl;
}
}

return 0;
}
```

### Python

```# cook your dish here
T = int(input())
while (T > 0):
a, b = map(int, input().split())

if (a == 0):
print("Liquid")
elif (b == 0):
print("Solid")
else:
print("Solution")

T = T - 1```

### Java

```/* package codechef; // don't place package name! */

import java.util.Scanner;
import java.lang.*;
import java.io.*;

/* Name of the class has to be "Main" only if the class is public. */
class Codechef
{
public static void main (String[] args) throws java.lang.Exception
{
Scanner input = new Scanner(System.in);
int test = input.nextInt();
while (test > 0){
int a = input.nextInt();
int b = input.nextInt();

if (a == 0){
System.out.println("Liquid");
}
else if (b == 0){
System.out.println("Solid");
}
else{
System.out.println("Solution");
}
test = test - 1;
}
}
}
```

Disclaimer: The above Problem (Which Mixture) is generated by CodeChef but the Solution is Provided by CodingBroz. This tutorial is only for Educational and Learning Purpose.