# Strings in C++ | HackerRank Solution

What’s up coderz, Today we will be solving Strings in C++ HackerRank Solution.

Contents

## Objective

C++ provides a nice alternative data type to manipulate strings, and the data type is conveniently called string. Some of its widely used features are the following:

Declaration:

string a = "abc";

Size:

int len = a.size();

Concatenate two strings:

string a = "abc";
string b = "def";
string c = a + b; // c = "abcdef".

Accessing ith element:

string s = "abc";
char   c0 = s[0];   // c0 = 'a'
char   c1 = s[1];   // c1 = 'b'
char   c2 = s[2];   // c2 = 'c'

s[0] = 'z';         // s = "zbc"

P.S.: We will use cin/cout to read/write a string.

## Input Format

You are given two strings, a and b, separated by a new line. Each string will consist of lower case Latin characters (‘a’-‘z’).

## Output Format

In the first line print two space-separated integers, representing the length of a and b respectively.

In the second line print the string produced by concatenating a and b (a+b).

In the third line print two strings separated by a space, aâ€™ and bâ€™. aâ€™ and bâ€™ are the same as a and b, respectively, except that their first characters are swapped.

Sample Input

abcd
ef

Sample Output

4 2
abcdef
ebcd af

## Explanation

• a = “abcd”
• b = “ef”
• |a| = 4
• |b| = 2
• a + b = “abcdef”
• aâ€™ = “ebcd”
• bâ€™ = “af”

## Solution – Strings in C++ HackerRank Solution

#include <iostream>
#include <string>
using namespace std;

int main() {
// Complete the program
string a,b;
cin >> a >> b ;
int l_of_a = a.size();
int l_of_b = b.size();
cout << l_of_a <<" "<<l_of_b << endl;
cout << a << b << endl;
char c1 = a[0];
char c2 = b[0];
a[0] = c2;
b[0] = c1;
cout << a <<" "<<b;
return 0;
}

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