Hello coders, today we are going to solve Smallest Number of Notes CodeChef Solution whose Problem Code is FLOW005.

Task
Consider a currency system in which there are notes of six denominations, namely, Rs. 1, Rs. 2, Rs. 5, Rs. 10, Rs. 50, Rs. 100.
If the sum of Rs. N is input, write a program to computer smallest number of notes that will combine to give Rs. N
Input Format
The first line contains an integer T, total number of testcases. Then follow T lines, each line contains an integer N.
Output Format
For each test case, display the smallest number of notes that will combine to give N, in a new line.
Constraints
- 1 ≤ T ≤ 1000
- 1 ≤ N ≤ 1000000
Example
Input
3
1200
500
242
Output
12
5
7
Solution – Smallest Number of Notes | CodeChef Solution
C++
#include <iostream> #include <vector> #include <cstdio> using namespace std; int T; int N; int main() { scanf("%d", &T); while (T--) { scanf("%d", &N); // Solve int sum = 0; std::vector<int> coins = { 100, 50, 10, 5, 2, 1 }; for (auto c : coins) { sum += N / c; N = N % c; } // Print answer printf("%d\n", sum); } return 0; }
Java
import java.util.*; class Note { public static void main(String[] args) { Scanner s = new Scanner(System.in); int t = s.nextInt(); //int p=0,q=0; while(t>0) { t--; int n = s.nextInt(); int rem=n%100; int count=n/100; count=count+(rem/50); rem=rem%50; count=count+(rem/10); rem=rem%10; count=count+(rem/5); rem=rem%5; count=count+(rem/2); rem=rem%2; count=count+(rem/1); rem=rem%1; System.out.println(count); } } }
Python
#Solution Provided by CodingBroz T = int(input()) a = [100, 50, 10, 5, 2, 1] for _ in range(T): n = int(input()) b = 0 for x in a: if (x <= n): b = b + (n // x ) n = n % x print(b)
Disclaimer: The above Problem (Smallest Number of Notes) is generated by CodeChef but the Solution is Provided by CodingBroz. This tutorial is only for Educational and Learning Purpose.