Simple Array Sum | HackerRank Solution

Hello coders, today we are going to solve Simple Array Sum HackerRank Solution which is a Part of HackerRank Algorithms Series.

Task

Given an array of integers, find the sum of its elements.

For example, if the array ar = [1, 2, 3], 1 + 2 + 3 = 6, so return 6.

Function Description

Complete the simpleArraySum function in the editor below. It must return the sum of the array elements as an integer.

simpleArraySum has the following parameter(s):

• ar: an array of integers

Input Format

The first line contains an integer, n, denoting the size of the array.
The second line contains n space-separated integers representing the array’s elements.

Constraints

• 0 < n, arr[i] <= 1000

Output Format

Print the sum of the array’s elements as a single integer.

Sample Input

6
1 2 3 4 10 11

Sample Output

31

Explanation

We print the sum of the array’s elements: 1 + 2 + 3 + 4 + 10 + 11 = 31.

Solution – Simple Array Sum

C++

#include <bits/stdc++.h>

using namespace std;

vector<string> split_string(string);

/*
 * Complete the simpleArraySum function below.
 */
int simpleArraySum(vector<int> ar) {
    /*
     * Write your code here.
     */
    int sum = 0;
    for(int i=0;i<ar.size();i++){
        sum+=ar[i];
    }
    return sum;
}

int main()
{
    ofstream fout(getenv("OUTPUT_PATH"));

    int ar_count;
    cin >> ar_count;
    cin.ignore(numeric_limits<streamsize>::max(), '\n');

    string ar_temp_temp;
    getline(cin, ar_temp_temp);

    vector<string> ar_temp = split_string(ar_temp_temp);

    vector<int> ar(ar_count);

    for (int ar_itr = 0; ar_itr < ar_count; ar_itr++) {
        int ar_item = stoi(ar_temp[ar_itr]);

        ar[ar_itr] = ar_item;
    }

    int result = simpleArraySum(ar);

    fout << result << "\n";

    fout.close();

    return 0;
}

vector<string> split_string(string input_string) {
    string::iterator new_end = unique(input_string.begin(), input_string.end(), [] (const char &x, const char &y) {
        return x == y and x == ' ';
    });

    input_string.erase(new_end, input_string.end());

    while (input_string[input_string.length() - 1] == ' ') {
        input_string.pop_back();
    }

    vector<string> splits;
    char delimiter = ' ';

    size_t i = 0;
    size_t pos = input_string.find(delimiter);

    while (pos != string::npos) {
        splits.push_back(input_string.substr(i, pos - i));

        i = pos + 1;
        pos = input_string.find(delimiter, i);
    }

    splits.push_back(input_string.substr(i, min(pos, input_string.length()) - i + 1));

    return splits;
}

Python

n = int(input().strip())
arr = [int(arr_temp) for arr_temp in input().strip().split(' ')]
print(sum(arr))

Java

import java.io.*;
import java.math.*;
import java.text.*;
import java.util.*;
import java.util.regex.*;

public class Solution {

    /*
     * Complete the simpleArraySum function below.
     */
    static int simpleArraySum(int[] ar) {
        /*
         * Write your code here.
         */
          int sum = 0;
        for(int i=0;i<ar.length;i++){
        sum+=ar[i];
        }
        return sum;

    }

    private static final Scanner scanner = new Scanner(System.in);

    public static void main(String[] args) throws IOException {
        BufferedWriter bufferedWriter = new BufferedWriter(new FileWriter(System.getenv("OUTPUT_PATH")));

        int arCount = Integer.parseInt(scanner.nextLine().trim());

        int[] ar = new int[arCount];

        String[] arItems = scanner.nextLine().split(" ");

        for (int arItr = 0; arItr < arCount; arItr++) {
            int arItem = Integer.parseInt(arItems[arItr].trim());
            ar[arItr] = arItem;
        }

        int result = simpleArraySum(ar);

        bufferedWriter.write(String.valueOf(result));
        bufferedWriter.newLine();

        bufferedWriter.close();
    }
}

Disclaimer: The above Problem (Simple Array Sum) is generated by Hacker Rank but the Solution is Provided by CodingBroz. This tutorial is only for Educational and Learning Purpose.