# Re.findall() & Re.finditer() in Python | HackerRank Solution

Hello coders, today we are going to solve Re.findall() & Re.finditer() HackerRank Solution in Python.

## Objective

re.findall()

The expression re.findall() returns all the non-overlapping matches of patterns in a string as a list of strings.

Code

``````>>> import re
>>> re.findall(r'\w','http://www.hackerrank.com/')
['h', 't', 't', 'p', 'w', 'w', 'w', 'h', 'a', 'c', 'k', 'e', 'r', 'r', 'a', 'n', 'k', 'c', 'o', 'm']``````

re.finditer()

The expression re.finditer() returns an iterator yielding `MatchObject` instances over all non-overlapping matches for the re pattern in the string.

Code

``````>>> import re
>>> re.finditer(r'\w','http://www.hackerrank.com/')
<callable-iterator object at 0x0266C790>
>>> map(lambda x: x.group(),re.finditer(r'\w','http://www.hackerrank.com/'))
['h', 't', 't', 'p', 'w', 'w', 'w', 'h', 'a', 'c', 'k', 'e', 'r', 'r', 'a', 'n', 'k', 'c', 'o', 'm']``````

You are given a string S. It consists of alphanumeric characters, spaces and symbols(`+`,`-`).
Your task is to find all the substrings of S that contains 2 or more vowels.
Also, these substrings must lie in between 2 consonants and should contain vowels only.

## Input Format

A single line of input containing string S.

## Constraints

• 0 < len(S) < 100

## Output Format

Print the matched substrings in their order of occurrence on separate lines.
If no match is found, print `-1`.

Sample Input

``rabcdeefgyYhFjkIoomnpOeorteeeeet``

Sample Output

``````ee
Ioo
Oeo
eeeee``````

Explanation

ee is located between consonant d and f.
Ioo is located between consonant k and m.
Oeo is located between consonant p and r.
eeeee is located between consonant t and t.

## Solution – Re.findall() & Re.finditer() in Python

```# Enter your code here. Read input from STDIN. Print output to STDOUT
import re

vowels = 'aeiou'
consonants = 'qwrtypsdfghjklzxcvbnm'
match = re.findall(r'(?<=[' + consonants + '])([' + vowels + ']{2,})(?=[' + consonants + '])', input(), flags=re.I)
print('\n'.join(match or ['-1']))```

Disclaimer: The above Problem (Re.findall() & Re.finditer()) is generated by Hacker Rank but the Solution is Provided by CodingBroz. This tutorial is only for Educational and Learning Purpose.