Hello coders, today we are going to solve Reduce Function HackerRank Solution in Python.
Given a list of rational numbers,find their product.
reduce() function applies a function of two arguments cumulatively on a list of objects in succession from left to right to reduce it to one value. Say you have a list, say
[1,2,3] and you have to find its sum.
>>> reduce(lambda x, y : x + y,[1,2,3]) 6
You can also define an initial value. If it is specified, the function will assume initial value as the value given, and then reduce. It is equivalent to adding the initial value at the beginning of the list. For example:
>>> reduce(lambda x, y : x + y, [1,2,3], -3) 3 >>> from fractions import gcd >>> reduce(gcd, [2,4,8], 3) 1
First line contains n, the number of rational numbers.
The ith of next n lines contain two integers each, the numerator( Ni ) and denominator( Di ) of the ith rational number in the list.
- 1 <= n <= 100
- 1 <= Ni, Di <= 109
Print only one line containing the numerator and denominator of the product of the numbers in the list in its simplest form, i.e. numerator and denominator have no common divisor other than 1.
Sample Input 0
3 1 2 3 4 10 6
Sample Output 0
Required product is 5 / 8
Solution – Reduce Function in Python
from fractions import Fraction from functools import reduce def product(fracs): t = Fraction(reduce(lambda x, y: x * y, fracs)) return t.numerator, t.denominator if __name__ == '__main__': fracs =  for _ in range(int(input())): fracs.append(Fraction(*map(int, input().split()))) result = product(fracs) print(*result)
Disclaimer: The above Problem (Reduce Function) is generated by Hacker Rank but the Solution is Provided by CodingBroz. This tutorial is only for Educational and Learning Purpose.