# Python Program to Find Largest of 3 Numbers

In this post, we will learn how to find the largest of 3 numbers using Python Programming language.

This program takes three numbers as input from the user, and compares all three of them to find the largest number using the if. . .else statement.

So, without further ado, let’s begin this tutorial.

Contents

## Python Program to Find Largest of 3 Numbers

```# Python Program to Find Largest of 3 Numbers
num1 = int(input("Enter first number: "))
num2 = int(input("Enter second number: "))
num3 = int(input("Enter third number: "))

# Finding largest number
if (num1 >= num2) and (num1 >= num3):
largest = num1
elif (num2 >= num1) and (num2 >= num3):
largest = num2
else:
largest = num3

# Displaying output
print("Largest number is: ", largest)
```

Output

``````Enter first number: 22
Enter second number: 27
Enter third number: 21
Largest number is:  27
``````

## How Does This Program Work ?

```num1 = int(input("Enter first number: "))
num2 = int(input("Enter second number: "))
num3 = int(input("Enter third number: "))
```

The user is asked to enter three integers.

```if (num1 >= num2) and (num1 >= num3):
largest = num1
```

Now, we compare whether num1 is greater than num2 and num3 or not. If the condition is true, then num1 is the largest number.

```elif (num2 >= num1) and (num2 >= num3):
largest = num2
```

If the above condition is false, we check whether the value of num2 is greater than num1 and num3 or not. If yes, then num2 is the largest number.

```else:
largest = num3
```

If neither of the two conditions are true, then it clearly means num3 is the largest number.

```# Displaying output
print("Largest number is: ", largest)
```

Finally, the largest number is displayed on the screen with the help of print() function.

## Conclusion

I hope after going through this post, you understand how to find the largest of 3 numbers using Python Programming language.

If you have any doubt regarding the program, feel free to contact us in the comment section. We will be delighted to assist you.