In this post, we will learn **how to check whether a year is a leap year or not using Python** Programming language.

A** leap year** has **366 days** (the extra day is the **29th February**). It comes after every four years.

To check whether a year is a leap or not, divide the year by** 4**. If it is fully divisible by **4**, then it is a leap year.

**Note:** To check years like 1200, 1300, 1500, 2700 etc., these years need to be divided by **400** to check whether they are leap or not.

So, without further ado, let’s begin this tutorial.

**Python Program to Check Leap Year**

# Python Program to Check Leap Year year = int(input("Enter the year: ")) # Checking Leap Year if year % 4 == 0 and year % 100 != 0: print(year, "is a leap year.") elif year % 400 == 0: print(year, "is a leap year.") elif year % 100 == 0: print(year, "is not a leap year.") else: print(year, "is not a leap year.")

**Output 1**

```
Enter the year: 2012
2012 is a leap year.
```

**Output 2**

```
Enter the year: 2030
2030 is not a leap year.
```

**How Does This Program Work ?**

year = int(input("Enter the year: "))

The user is asked to enter the year.

if year % 4 == 0 and year % 100 != 0: print(year, "is a leap year.")

Then, we use the** if **statement to check whether the year is divisible by** 4 **and not divisible by** 100**. If the statement is **true**, then the entered year is a **leap year**.

elif year % 400 == 0: print(year, "is a leap year.")

If the year is divisible by **400**, then it’s a leap year.

elif year % 100 == 0: print(year, "is not a leap year.")

However, if the year is divisible by** 100**, then the year is not a leap year.

else: print(year, "is not a leap year.")

And in the end, if the year is not divisible by **4**, then the entered year is not a leap year.

**Conclusion**

I hope after going through this post, you understand** how to check whether a year is a leap year or not using Python** Programming language.

If you have any doubt regarding the topic, feel free to contact us in the comment section. We will be delighted to solve your query.

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