# Min and Max in Python | HackerRank Solution

Hello coders, today we are going to solve Min and Max HackerRank Solution in Python.

Contents

## Objective

min

The tool min returns the minimum value along a given axis.

``````import numpy

my_array = numpy.array([[2, 5],
[3, 7],
[1, 3],
[4, 0]])

print numpy.min(my_array, axis = 0)         #Output : [1 0]
print numpy.min(my_array, axis = 1)         #Output : [2 3 1 0]
print numpy.min(my_array, axis = None)      #Output : 0
print numpy.min(my_array)                   #Output : 0``````

By default, the axis value is `None`. Therefore, it finds the minimum over all the dimensions of the input array.

max

The tool max returns the maximum value along a given axis.

``````import numpy

my_array = numpy.array([[2, 5],
[3, 7],
[1, 3],
[4, 0]])

print numpy.max(my_array, axis = 0)         #Output : [4 7]
print numpy.max(my_array, axis = 1)         #Output : [5 7 3 4]
print numpy.max(my_array, axis = None)      #Output : 7
print numpy.max(my_array)                   #Output : 7``````

By default, the axis value is `None`. Therefore, it finds the maximum over all the dimensions of the input array.

You are given a 2-D array with dimensions N X M.
Your task is to perform the min function over axis 1 and then find the max of that.

## Input Format

The first line of input contains the space separated values of N and M.
The next N lines contains M space separated integers.

## Output Format

Compute the min along axis 1 and then print the max of that result.

Sample Input

``````4 2
2 5
3 7
1 3
4 0``````

Sample Output

``3``

Explanation

The min along axis 1 = [2, 3, 1, 0]
The max of [2, 3, 1, 0] = 3

## Solution – Min and Max in Python

```import numpy as np
N, M = map(int, input().split())
print(np.array([input().split() for _ in range(int(N))], int).min(1).max())```

Disclaimer: The above Problem (Min and Max) is generated by Hacker Rank but the Solution is Provided by CodingBroz. This tutorial is only for Educational and Learning Purpose.