Hello coders, today we will be solving Merge The Tools in Python Hacker Rank Solution.
Consider the following:
A string, s, of length n where s = c0c1. . . . cn-1.
An integer, k, where k is a factor of n.
We can split s into n/k substrings where each subtring, ti, consists of a contiguous block of k characters in s. Then, use each ti to create string ui such that:
The characters in ui are a subsequence of the characters in ti.
Any repeat occurrence of a character is removed from the string such that each character in ui occurs exactly once. In other words, if the character at some index j in ti occurs at a previous index < j in ti, then do not include the character in string ui.
Given s and k, print n/k lines where each line i denotes string ui.
s = “AAABCADDE”
k = 3
There are three substrings of length 3 to consider: ‘AAA’, ‘BCA’ and ‘DDE’. The first substring is all ‘A’ characters, so u1 = ‘A’. The second substring has all distinct characters, so u2 = ‘BCA’. The third substring has 2 different characters, so u3 = ‘DE’. Note that a subsequence maintains the original order of characters encountered. The order of characters in each subsequence shown is important.
Complete the merge_the_tools function in the editor below.
merge_the_tools has the following parameters:
- string s: the string to analyze
- int k: the size of substrings to analyze
Print each subsequence on a new line. There will be n/k of them. No return value is expected.
The first line contains a single string, s.
The second line contains an integer, k, the length of each substring.
- 1 <= n <= 10^4, where n is the length of s
- 1 <= k <= n
- It is guaranteed that n is a multiple of k.
STDIN Function ----- -------- AABCAAADA s = 'AABCAAADA' 3 k = 3
AB CA AD
Split s into n/k = 9/3 = 3 equal parts of length k = 3. Convert each ti to ui by removing any subsequent occurrences of non-distinct characters in ti:
- t0 = “AAB” – u0 = “AB”
- t1 = “CAA” – u1 = “CA”
- t2 = “ADA” – u2 = “AD”
Print each ui on a new line.
Solution – Merge The Tools in Python – Hacker Rank Solution
def merge_the_tools(string, k): # your code goes here temp =  len_temp = 0 for item in string: len_temp += 1 if item not in temp: temp.append(item) if len_temp == k: print (''.join(temp)) temp =  len_temp = 0 if __name__ == '__main__': string, k = input(), int(input()) merge_the_tools(string, k)
Disclaimer: The above Problem (Merge The Tools) is generated by Hacker Rank but the Solution is generated by CodingBroz. This tutorial is only for Educational and Learning purpose.