Hello coders, today we are going to solve **Lucky Four CodeChef Solution **whose Problem code is **LUCKFOUR**.

Contents

**Problem**

Kostya likes the number 4 much. Of course! This number has such a lot of properties, like:

- Four is the smallest composite number;
- It is also the smallest Smith number;
- The smallest non-cyclic group has four elements;
- Four is the maximal degree of the equation that can be solved in radicals;
- There is four-color theorem that states that any map can be colored in no more than four colors in such a way that no two adjacent regions are colored in the same color;
- Lagrange’s four-square theorem states that every positive integer can be written as the sum of at most four square numbers;
- Four is the maximum number of dimensions of a real division algebra;
- In bases 6 and 12, 4 is a 1-automorphic number;
- And there are a lot more cool stuff about this number!

Impressed by the power of this number, Kostya has begun to look for occurrences of four anywhere. He has a list of T integers, for each of them he wants to calculate the number of occurrences of the digit 4 in the decimal representation. He is too busy now, so please help him.

**Input**

The first line of input consists of a single integer T, denoting the number of integers in Kostya’s list.

Then, there are T lines, each of them contain a single integer from the list.

**Output**

Output T lines. Each of these lines should contain the number of occurences of the digit 4 in the respective integer from Kostya’s list.

**Constraints**

**1 â‰¤ T â‰¤ 10^5****(Subtask 1): 0 â‰¤ Numbers from the list â‰¤ 9 – 33 points.****(Subtask 2): 0 â‰¤ Numbers from the list â‰¤ 109 – 67 points.**

**Example**

**Input:**

5 447474 228 6664 40 81

**Output:**

4 0 1 1 0

**Solution – Lucky Four codeChef Solution**

**Python 3**

T = int(input()) for _ in range(T): n = int(input()) count = 0 while n > 0: if n % 10 == 4: count += 1 n = n // 10 print(count)

**Disclaimer:** The above Problem **(Lucky Four)** is generated by **CodeChef** but the Solution is provided by **CodingBroz**. This tutorial is only for **Educational** and **Learning** Purposes.