Lapindromes CodeChef Solution

Hello, coders today we will be solving Lapindromes CodeChef Problem which is a part of CodeChef DSA Learning Series.

Problem 

Lapindrome is defined as a string which when split in the middle, gives two halves having the same characters and same frequency of each character. If there are odd number of characters in the string, we ignore the middle character and check for lapindrome. For example gaga is a lapindrome, since the two halves ga and ga have the same characters with same frequency. Also, abccab, rotor and xyzxy are a few examples of lapindromes. Note that abbaab is NOT a lapindrome. The two halves contain the same characters but their frequencies do not match.

Your task is simple. Given a string, you need to tell if it is a lapindrome.

Input

First line of input contains a single integer T, the number of test cases.

Each test is a single line containing a string S composed of only lowercase English alphabet.

Output

For each test case, output on a separate line: “YES” if the string is a lapindrome and “NO” if it is not.

Constraints

• 1 ≤ T ≤ 100
• 2 ≤ |S| ≤ 1000, where |S| denotes the length of S

Example

Input:

6
gaga
abcde
rotor
xyzxy
abbaab
ababc

Output:

YES
NO
YES
YES
NO
NO

Solution – Lapindromes CodeChef Solution

Java

/* package codechef; // don't place package name! */
import java.util.*;
import java.lang.*;
import java.io.*;

/* Name of the class has to be "Main" only if the class is public. */
class Codechef
{
	public static void main (String[] args) throws java.lang.Exception
	{
		// your code goes here
		Scanner sc = new Scanner(System.in);
		int t = sc.nextInt();
		while(t--!=0)
		{
		    String S = sc.next();
		    int len = S.length();
		    String half1="",half2="";
		    int c=0;
		    half1=S.substring(0,len/2);
		    if(len%2==0) half2=S.substring(len/2);
		    else if(len%2!=0) half2=S.substring(len/2+1);
		    char h1[] = half1.toCharArray();
		    char h2[] = half2.toCharArray();
		    Arrays.sort(h1);
		    Arrays.sort(h2);
    String a = String.copyValueOf(h1);
    String b = String.copyValueOf(h2);
    
		    if(a.equals(b)) System.out.println("YES");
		    else System.out.println("NO");
		}
		sc.close();
	}
}

C++

#include <bits/stdc++.h>
using namespace std;

int main() {
	int t;
	cin>>t;
	while(t--)
	{
	    string s;
	    cin>>s;
	    string first, second;
	    int n = s.length();
	    for(int i=0;i<n/2;i++)
	    {
	        first+=s[i];
	        second+=s[n-i-1];
	    }
	    sort(first.begin(), first.end());
	    sort(second.begin(), second.end());
	    
	    if(first == second)
	    {
	        cout<<"YES\n";
	    }
	    else
	    {
	        cout<<"NO\n";
	    }
	}
}

Disclaimer: The above problem (Lapindromes: LAPIN) is generated by CodeChef but the solution is provided by CodingBroz.

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