Java Varargs – Simple Addition | HackerRank Solution

Hello coders, today we are going to solve Java Varargs – Simple Addition HackerRank Solution.

Problem

You are given a class Solution and its main method in the editor.
Your task is to create the class Add and the required methods so that the code prints the sum of the numbers passed to the function add.

Note: Your add method in the Add class must print the sum as given in the Sample Output

Input Format

There are six lines of input, each containing an integer.

Output Format

There will be only four lines of output. Each line contains the sum of the integers passed as the parameters to add in the main method.

Sample Input

 1
 2
 3
 4
 5
 6

Sample Output

 1+2=3
 1+2+3=6
 1+2+3+4+5=15
 1+2+3+4+5+6=21

Solution – Java Varargs – Simple Addition

import java.io.*;
import java.lang.reflect.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;


class Add {
    public void add(int... intArgs) {
        int sum = 0;
        String separator = "";
        for (int i : intArgs) {
            sum += i;
            System.out.print(separator + i);
            separator = "+";            
        }
        System.out.println("=" + sum);
    }
}


public class Solution {

    public static void main(String[] args) {
       try{
			BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
			int n1=Integer.parseInt(br.readLine());
			int n2=Integer.parseInt(br.readLine());
			int n3=Integer.parseInt(br.readLine());
			int n4=Integer.parseInt(br.readLine());
			int n5=Integer.parseInt(br.readLine());
			int n6=Integer.parseInt(br.readLine());
			Add ob=new Add();
			ob.add(n1,n2);
			ob.add(n1,n2,n3);
			ob.add(n1,n2,n3,n4,n5);	
			ob.add(n1,n2,n3,n4,n5,n6);
			Method[] methods=Add.class.getDeclaredMethods();
			Set<String> set=new HashSet<>();
			boolean overload=false;
			for(int i=0;i<methods.length;i++)
			{
				if(set.contains(methods[i].getName()))
				{
					overload=true;
					break;
				}
				set.add(methods[i].getName());
				
			}
			if(overload)
			{
				throw new Exception("Overloading not allowed");
			}
			}
			catch(Exception e)
			{
				e.printStackTrace();
			}
		}
		
	
	

}

Disclaimer: The above Problem ( Java Varargs – Simple Addition ) is generated by Hacker Rank but the Solution is Provided by CodingBroz. This tutorial is only for Educational and Learning Purpose.