Hello coders, today we are going to solve Java If-Else HackerRank Solution.

Problem
In this challenge, we test your knowledge of using if-else conditional statements to automate decision-making processes. An if-else statement has the following logical flow:

Task
Given an integer, n, perform the following conditional actions :
- If n is odd, print Weird
- If n is even and in the inclusive range of 2 to 5, print Not Weird
- If n is even and in the inclusive range of 6 to 20, print Weird
- If n is even and greater than 20, print Not Weird
Input Format
A single line containing a positive integer, n.
Constraints
1 <= n <= 100
Output Format
Print Weird if the number is weird; otherwise, print Not Weird.
Sample input 0
3
Sample output 0
Weird
Sample input 1
24
Sample output 1
Not Weird
Explanation
Sample Case 0: n=3, where n is odd and odd numbers are weird, so we print Weird
.
Sample Case 1: n=24, where n>20 and n is even, so it isn’t weird. Thus, we print Not Weird
.
Solution – Java If-Else
import java.io.*; import java.math.*; import java.security.*; import java.text.*; import java.util.*; import java.util.concurrent.*; import java.util.regex.*; public class Solution { private static final Scanner scanner = new Scanner(System.in); public static void main(String[] args) { int N = scanner.nextInt(); scanner.skip("(\r\n|[\n\r\u2028\u2029\u0085])?"); scanner.close(); if (N%2==1){ System.out.println("Weird"); } else if(N%2==0 && (N>=2 && N<=5)){ System.out.println("Not Weird"); } else if(N%2==0 && (N>5 && N<=20)){ System.out.println("Weird"); } else if(N%2==0 && (N>20 && N<=100)){ System.out.println("Not Weird"); } } }
Disclaimer: The above Problem (Java If-Else) is generated by Hacker Rank but the Solution is Provided by CodingBroz. This tutorial is only for Educational and Learning Purpose.