Java If-Else | HackerRank Solution

Hello coders, today we are going to solve Java If-Else HackerRank Solution.

Problem

In this challenge, we test your knowledge of using if-else conditional statements to automate decision-making processes. An if-else statement has the following logical flow:

Task

Given an integer, n, perform the following conditional actions :

• If n is odd, print Weird
• If n is even and in the inclusive range of 2 to 5, print Not Weird
• If n is even and in the inclusive range of 6 to 20, print Weird
• If n is even and greater than 20, print Not Weird

Input Format

A single line containing a positive integer, n.

Constraints

1 <= n <= 100

Output Format

Print Weird if the number is weird; otherwise, print Not Weird.

Sample input 0

 3

Sample output 0

 Weird

Sample input 1

 24

Sample output 1

 Not Weird

Explanation

Sample Case 0: n=3, where n is odd and odd numbers are weird, so we print Weird.

Sample Case 1: n=24, where n>20 and n is even, so it isn’t weird. Thus, we print Not Weird.

Solution – Java If-Else

import java.io.*;
import java.math.*;
import java.security.*;
import java.text.*;
import java.util.*;
import java.util.concurrent.*;
import java.util.regex.*;

public class Solution {

    

    private static final Scanner scanner = new Scanner(System.in);

    public static void main(String[] args) {
        int N = scanner.nextInt();
        scanner.skip("(\r\n|[\n\r\u2028\u2029\u0085])?");

        scanner.close();
      if (N%2==1){
          System.out.println("Weird");
      }
      else if(N%2==0 && (N>=2 && N<=5)){
          System.out.println("Not Weird");
      }
      else if(N%2==0 && (N>5 && N<=20)){
          System.out.println("Weird");
      }
      else if(N%2==0 && (N>20 && N<=100)){
          System.out.println("Not Weird");
      }


    }
}

Disclaimer: The above Problem (Java If-Else) is generated by Hacker Rank but the Solution is Provided by CodingBroz. This tutorial is only for Educational and Learning Purpose.