Java Exception Handling | HackerRank Solution

Hello coders, today we are going to solve Java Exception Handling HackerRank Solution.

Java Exception Handling

Problem

You are required to compute the power of a number by implementing a calculator. Create a class MyCalculator which consists of a single method long power(int, int). This method takes two integers, n and p, as parameters and finds np. If either n or p is negative, then the method must throw an exception which says “ n or p should not be negative “. Also, if both n and p are zero, then the method must throw an exception which says “n or p should not be zero .
For example, -4 and -5 would result in java.lang.Exception : n or p should not be negative.

Complete the function power in class MyCalculator and return the appropriate result after the power operation or an appropriate exception as detailed above.

Input Format

Each line of the input contains two integers, n and p. The locked stub code in the editor reads the input and sends the values to the method as parameters.

Constraint

  • -10 <= n <= 10
  • -10 <= p <= 10

Output Format

Each line of the output contains the result np, if both n and p are positive. If either n or p is negative, the output contains “n and p should be non-negative”. If both n and p are zero, the output contains “n and p should not be zero.”. This is printed by the locked stub code in the editor.

Sample Input

3 5
2 4
0 0
-1 -2
-1 3

Sample Output

 243
 16
 java.lang.Exception: n and p should not be zero.
 java.lang.Exception: n or p should not be negative.
 java.lang.Exception: n or p should not be negative.

Explanation

  • In the first two cases, both n and p are postive. So, the power function returns the answer correctly.
  • In the third case, both n and p are zero. So, the exception, “n and p should not be zero.”, is printed.
  • In the last two cases, at least one out of n and p is negative. So, the exception, “n or p should not be negative.”, is printed for these two cases.

Solution – Java Exception Handling

import java.util.Scanner;
import java.math.*;
class MyCalculator {
    /*
    * Create the method long power(int, int) here.
    */
  
    public static long power(int a,int b) throws Exception{
        long la = a;
        long lb = b;
             long c = (long)Math.pow(la,lb);
             if(la==0 && lb==0)  {
                 throw new Exception("n and p should not be zero.");

             }
             else if(la<0 || lb <0) {
             throw new Exception("n or p should not be negative.");
             
             }
             else
             return c;
      
    }
   
  
}

public class Solution {
    public static final MyCalculator my_calculator = new MyCalculator();
    public static final Scanner in = new Scanner(System.in);
    
    public static void main(String[] args) {
        while (in .hasNextInt()) {
            int n = in .nextInt();
            int p = in .nextInt();
            
            try {
                System.out.println(my_calculator.power(n, p));
            } catch (Exception e) {
                System.out.println(e);
            }
        }
    }
}

Disclaimer: The above Problem ( Java Exception Handling ) is generated by Hacker Rank but the Solution is Provided by CodingBroz. This tutorial is only for Educational and Learning Purpose.

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