Java Datatypes | HackerRank Solution

Hello coders, today we are going to solve Java Datatypes HackerRank Solution.

Java Datatypes


Java has 8 primitive data types; char, boolean, byte, short, int, long, float, and double. For this exercise, we’ll work with the primitives used to hold integer values (byte, short, int, and long):

  • A byte is an 8-bit signed integer.
  • A short is a 16-bit signed integer.
  • An int is a 32-bit signed integer.
  • A long is a 64-bit signed integer.

Given an input integer, you must determine which primitive data types are capable of properly storing that input. To get you started, a portion of the solution is provided for you in the editor.

Input Format

The first line contains an integer, T, denoting the number of test cases.
Each test case, T, is comprised of a single line with an integer, n, which can be arbitrarily large or small.

Output Format

For each input variable n and appropriate primitive datatype, you must determine if the given primitives are capable of storing it. If yes, then print:

 n can be fitted in:
 * dataType

If there is more than one appropriate data type, print each one on its own line and order them by size (i.e.:

byte < short < int < long ).

If the number cannot be stored in one of the four aforementioned primitives, print the line:

 n can't be fitted anywhere.

Sample Input


Sample Input

 -150 can be fitted in:
 * short
 * int
 * long
 150000 can be fitted in:
 * int
 * long
 1500000000 can be fitted in:
 * int
 * long
 213333333333333333333333333333333333 can't be fitted anywhere.
 -100000000000000 can be fitted in:
 * long


-150 can be stored in a short, an int, or a long.

213333333333333333333333333333333333 is very large and is outside of the allowable range of values for the primitive data types discussed in this problem.

Solution – Java Datatypes

import java.util.*;

class Solution{
    public static void main(String []argh)
        Scanner sc = new Scanner(;
        int t=sc.nextInt();
        for(int i=0;i<t;i++)
                long x=sc.nextLong();
                System.out.println(x+" can be fitted in:");
                if(x>=-128 && x<=127)System.out.println("* byte");
                 if (x>=-32768 && x<=32767)System.out.println("* short");
                 if (x>=-2147483648 && x<=2147483647)System.out.println("* int");
                 if (x>=-9223372036854775808L && x<=9223372036854775807L)System.out.println("* long");
            catch(Exception e)
                System.out.println(" can't be fitted anywhere.");


Disclaimer: The above Problem ( Java Datatypes ) is generated by Hacker Rank but the Solution is Provided by CodingBroz. This tutorial is only for Educational and Learning Purpose.

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