# Java Datatypes | HackerRank Solution

Hello coders, today we are going to solve Java Datatypes HackerRank Solution.

Contents

## Problem

Java has 8 primitive data types; char, boolean, byte, short, int, long, float, and double. For this exercise, we’ll work with the primitives used to hold integer values (byte, short, int, and long):

• A byte is an 8-bit signed integer.
• A short is a 16-bit signed integer.
• An int is a 32-bit signed integer.
• A long is a 64-bit signed integer.

Given an input integer, you must determine which primitive data types are capable of properly storing that input. To get you started, a portion of the solution is provided for you in the editor.

## Input Format

The first line contains an integer, T, denoting the number of test cases.
Each test case, T, is comprised of a single line with an integer, n, which can be arbitrarily large or small.

## Output Format

For each input variable n and appropriate primitive datatype, you must determine if the given primitives are capable of storing it. If yes, then print:

`````` n can be fitted in:
* dataType``````

If there is more than one appropriate data type, print each one on its own line and order them by size (i.e.:

byte < short < int < long ).

If the number cannot be stored in one of the four aforementioned primitives, print the line:

`` n can't be fitted anywhere.``

Sample Input

`````` 5
-150
150000
1500000000
213333333333333333333333333333333333
-100000000000000``````

Sample Input

`````` -150 can be fitted in:
* short
* int
* long
150000 can be fitted in:
* int
* long
1500000000 can be fitted in:
* int
* long
213333333333333333333333333333333333 can't be fitted anywhere.
-100000000000000 can be fitted in:
* long``````

Explanation

-150 can be stored in a short, an int, or a long.

213333333333333333333333333333333333 is very large and is outside of the allowable range of values for the primitive data types discussed in this problem.

## Solution –Java Datatypes

```import java.util.*;
import java.io.*;

class Solution{
public static void main(String []argh)
{
Scanner sc = new Scanner(System.in);
int t=sc.nextInt();
for(int i=0;i<t;i++)
{
try
{
long x=sc.nextLong();
System.out.println(x+" can be fitted in:");
if(x>=-128 && x<=127)System.out.println("* byte");
if (x>=-32768 && x<=32767)System.out.println("* short");
if (x>=-2147483648 && x<=2147483647)System.out.println("* int");
if (x>=-9223372036854775808L && x<=9223372036854775807L)System.out.println("* long");
}
catch(Exception e)
{
System.out.println(sc.next()+" can't be fitted anywhere.");
}

}
}
}

```

Disclaimer: The above Problem ( Java Datatypes ) is generated by Hacker Rank but the Solution is Provided by CodingBroz. This tutorial is only for Educational and Learning Purpose.