# Java BigDecimal | HackerRank Solution

Hello coders, today we are going to solve Java BigDecimal HackerRank Solution.

Contents

## Problem

Java’s BigDecimal class can handle arbitrary-precision signed decimal numbers. Let’s test your knowledge of them!

Given an array, s, of n real number strings, sort them in descending order — but wait, there’s more! Each number must be printed in the exact same format as it was read from stdin, meaning that .1 is printed as .1, and 0.1 is printed as 0.1. If two numbers represent numerically equivalent values (e.g., .1≡0.1), then they must be listed in the same order as they were received as input).

Complete the code in the unlocked section of the editor below. You must rearrange array s‘s elements according to the instructions above.

## Input Format

The first line consists of a single integer, n, denoting the number of integer strings.
Each line i of the n subsequent lines contains a real number denoting the value of si.

#### Constraints

• 1 ≤ n 200
• Each si has the most 300 digits.

## Output Format

Locked stub code in the editor will print the contents of array s to stdout. You are only responsible for reordering the array’s elements.

#### Sample Input

`````` 9
-100
50
0
56.6
90
0.12
.12
02.34
000.000``````

#### Sample Input

`````` 90
56.6
50
02.34
0.12
.12
0
000.000
-100``````

## Solution –Java BigDecimal

```import java.math.BigDecimal;
import java.util.*;
class Solution{

public static void main(String []args){
//Input
Scanner sc= new Scanner(System.in);
int n=sc.nextInt();
String []s=new String[n+2];
for(int i=0;i<n;i++){
s[i]=sc.next();
}
sc.close();

for(int i=0;i<n;i++)
{
//inserting string values to bigdecimal
BigDecimal First=new BigDecimal(s[i]);
int index=i;
for(int j=i+1;j<n;j++)
{
//second BigDecimal to compare the first Bigdecimal
BigDecimal Second=new BigDecimal(s[j]);

//comparing if First element is greater that second element
//if the First element is greater than Second element than compareTo() returns 1

if(Second.compareTo(First)==1){
First=Second;
index=j;
}
}

//temporary variable to store s[i] value

String temp=s[i];
s[i]=s[index];
s[index]=temp;
}

//Output
for(int i=0;i<n;i++)
{
System.out.println(s[i]);
}
}

}```

Disclaimer: The above Problem ( Java BigDecimal ) is generated by Hacker Rank but the Solution is Provided by CodingBroz. This tutorial is only for Educational and Learning Purpose.