Java BigDecimal | HackerRank Solution

Hello coders, today we are going to solve Java BigDecimal HackerRank Solution.

Problem

Java’s BigDecimal class can handle arbitrary-precision signed decimal numbers. Let’s test your knowledge of them!

Given an array, s, of n real number strings, sort them in descending order — but wait, there’s more! Each number must be printed in the exact same format as it was read from stdin, meaning that .1 is printed as .1, and 0.1 is printed as 0.1. If two numbers represent numerically equivalent values (e.g., .1≡0.1), then they must be listed in the same order as they were received as input).

Complete the code in the unlocked section of the editor below. You must rearrange array s‘s elements according to the instructions above.

Input Format

The first line consists of a single integer, n, denoting the number of integer strings.
Each line i of the n subsequent lines contains a real number denoting the value of s_i.

Constraints

• 1 ≤ n ≤ 200
• Each s_i has the most 300 digits.

Output Format

Locked stub code in the editor will print the contents of array s to stdout. You are only responsible for reordering the array’s elements.

Sample Input

 9
 -100
 50
 0
 56.6
 90
 0.12
 .12
 02.34
 000.000

Sample Input

 90
 56.6
 50
 02.34
 0.12
 .12
 0
 000.000
 -100

Solution – Java BigDecimal

import java.math.BigDecimal;
import java.util.*;
class Solution{

    public static void main(String []args){
        //Input
        Scanner sc= new Scanner(System.in);
        int n=sc.nextInt();
        String []s=new String[n+2];
        for(int i=0;i<n;i++){
            s[i]=sc.next();
        }
      	sc.close();

        //Write your code here

for(int i=0;i<n;i++)
{
    //inserting string values to bigdecimal
    BigDecimal First=new BigDecimal(s[i]);
    int index=i;
    for(int j=i+1;j<n;j++)
    {
        //second BigDecimal to compare the first Bigdecimal
        BigDecimal Second=new BigDecimal(s[j]);

        //comparing if First element is greater that second element
        //if the First element is greater than Second element than compareTo() returns 1

        if(Second.compareTo(First)==1){
            First=Second;
            index=j;
        }
    }

    //temporary variable to store s[i] value

        String temp=s[i];
        s[i]=s[index];
        s[index]=temp;
}
      
        //Output
        for(int i=0;i<n;i++)
        {
            System.out.println(s[i]);
        }
    }

}

Disclaimer: The above Problem ( Java BigDecimal ) is generated by Hacker Rank but the Solution is Provided by CodingBroz. This tutorial is only for Educational and Learning Purpose.