# Higher Than 75 Marks in SQL | HackerRank Solution

Hello coders, today we are going to solve Higher Than 75 Marks HackerRank Solution in SQL.

## Problem

Query the Name of any student in STUDENTS who scored higher than 75 Marks. Order your output by the last three characters of each name. If two or more students both have names ending in the same last three characters (i.e.: Bobby, Robby, etc.), secondary sort them by ascending ID.

## Input Format

The STUDENTS table is described as follows:
contains uppercase (`A``Z`) and lowercase (`a``z`) letters.

Sample Input

Sample Output

``````Ashley
Julia
Belvet``````

## Explanation

Only Ashley, Julia, and Belvet have Marks > 75. If you look at the last three characters of each of their names, there are no duplicates and ‘ley’ < ‘lia’ < ‘vet’.

## Solution – Higher Than 75 Marks in SQL

### MySQL

`SELECT name FROM students WHERE marks > 75 ORDER BY SUBSTR(name, LENGTH(name)-2, 3), id;`

Disclaimer: The above Problem (Higher Than 75 Marks) is generated by Hacker Rank but the Solution is Provided by CodingBroz. This tutorial is only for Educational and Learning Purpose.

### 2 thoughts on “Higher Than 75 Marks in SQL | HackerRank Solution”

1. select name from
(select id, name, marks, right (name,3) as Y from students order by Y,id) A
where marks >75;

2. For Microsoft SQL Server code:
select name from students where marks > 75 order by substring(name, len(name)-2, 3), id