Hello coders, today we are going to solve Higher Than 75 Marks HackerRank Solution in SQL.
Problem
Query the Name of any student in STUDENTS who scored higher than 75 Marks. Order your output by the last three characters of each name. If two or more students both have names ending in the same last three characters (i.e.: Bobby, Robby, etc.), secondary sort them by ascending ID.
Input Format
| Column | Type |
|---|---|
| ID | Integer |
| Name | String |
| Marks | Integer |
The STUDENTS table is described as follows:
contains uppercase (A–Z) and lowercase (a–z) letters.
Sample Input
| ID | Name | Marks |
|---|---|---|
| 1 | Ashley | 81 |
| 2 | Samantha | 75 |
| 3 | Julia | 76 |
| 4 | Belvet | 84 |
Sample Output
Ashley
Julia
BelvetExplanation
Only Ashley, Julia, and Belvet have Marks > 75. If you look at the last three characters of each of their names, there are no duplicates and ‘ley’ < ‘lia’ < ‘vet’.
Solution – Higher Than 75 Marks in SQL
MySQL
SELECT name FROM students WHERE marks > 75 ORDER BY SUBSTR(name, LENGTH(name)-2, 3), id;
Disclaimer: The above Problem (Higher Than 75 Marks) is generated by Hacker Rank but the Solution is Provided by CodingBroz. This tutorial is only for Educational and Learning Purpose.
select name from
(select id, name, marks, right (name,3) as Y from students order by Y,id) A
where marks >75;