Grading Students | HackerRank Solution

Hello coders, today we are going to solve Grading Students HackerRank Solution which is a Part of HackerRank Algorithm Series.

Task

HackerLand University has the following grading policy:

• Every student receives a grade in the inclusive range from 0 to 100.
• Any grade less than 40 is a failing grade.

Sam is a professor at the university and likes to round each student’s grade according to these rules:

• If the difference between the grade and the next multiple of 5 is less than 3, round grade up to the next multiple of 5.
• If the value of grade is less than 38, no rounding occurs as the result will still be a failing grade.

Examples

• grade = 84 round to 85 (85 – 84 is less than 3)
• grade = 29 do not round (result is less than 40)
• grade = 57 do not round (60 – 57 is 3 or higher)

Given the initial value of grade for each of Sam’s n students, write code to automate the rounding process.

Function Description

Complete the function gradingStudents in the editor below.

gradingStudents has the following parameter(s):

• int grades[n]: the grades before rounding

Returns

• int[n]: the grades after rounding as appropriate

Input Format

The first line contains a single integer, n, the number of students.
Each line i of the n subsequent lines contains a single integer, grades[i].

Constraints

• 1 <= n <= 60
• 0 <= grades[i] <= 100

Sample Input 0

4
73
67
38
33

Sample Output 0

75
67
40
33

Explanation 0

1. Student 1 received a 73, and the next multiple of 5 from 73 is 75. Since 75 – 73 < 3, the student’s grade is rounded to 75.
2. Student 2 received a 67, and the next multiple of 5 from 67 is 70. Since 70 – 67 = 3, the grade will not be modified and the student’s final grade is 67.
3. Student 3 received a 38, and the next multiple of 5 from 38 is 40. Since 40 – 38 < 3, the student’s grade will be rounded to 40.
4. Student 4 received a grade below 33, so the grade will not be modified and the student’s final grade is 33.

Solution – Grading Students

C++

#include <bits/stdc++.h>
using namespace std;

void solution() {
     int n, x;
     cin>>n;
     for(int i=0; i<n; i++){
        cin>>x;
        if(x>=38 and x%5>=3){
            while(x%5!=0){
               x++;
            }
        }
        cout<<x<<endl;
     }
}

int main () {
    solution();
    return 0;
}

Python

n = int(input().strip())
for a0 in range(n):
    grade = int(input().strip())

    if grade >= 38:
        mod5 = grade % 5
        if mod5 >= 3:
            grade = grade + (5 - mod5)
    print(grade)

Disclaimer: The above Problem (Grading Students) is generated by Hacker Rank but the Solution is Provided by CodingBroz. This tutorial is only for Educational and Learning Purpose.