# For Loop in C++ | HackerRank Solution

Today we will be solving For Loop in C++ Hackerrank Problem.

## Objective

In this challenge, you will learn the usage of the for loop, which is a programming language statement which allows code to be executed until a terminal condition is met. They can even repeat forever if the terminal condition is never met.

The syntax for the for loop is:

``````for ( <expression_1> ; <expression_2> ; <expression_3> )
<statement>

expression_1 is used for initializing variables which are generally used for controlling the terminating flag for the loop.
expression_2 is used to check for the terminating condition. If this evaluates to false, then the loop is terminated.
expression_3 is generally used to update the flags/variables.

The following loop initializes i to 0, tests that i is less than 10, and increments i at every iteration. It will execute 10 times.

for(int i = 0; i < 10; i++) {
...
}
``````

To learn about Loops and for loops in c in more details and depth. Read this.

For each integer n in the interval [a,b] (given as input) :

• If 1<=n<=9, then print the English representation of it in lowercase. That is “one” for 1, “two” for 2, and so on.
• Else if n>9 and it is an even number, then print “even”.
• Else if n>9 and it is an odd number, then print “odd”.

## InputFormat

The first line contains an integer, a.

The second line contains an integer, b.

1<=a<=b<=10^6

## OutputFormat

Print the appropriate English representation,even, or odd, based on the conditions described in the ‘task’ section.

Note: [a,b] = {x ∈ Z | axb}

• Sample Input

8

11

• Sample Output

eight

nine

even

odd

## SOLUTIONS–For Loop in C++

```#include &lt;iostream&gt;
#include &lt;cstdio&gt;
using namespace std;

int main() {
// Complete the code.
int a,b;
cin &gt;&gt; a &gt;&gt; b;
for(int i = a ; i&lt;=b ; i++)
{
if((a&gt;=1 &amp;&amp; a&lt;=9))
{
string name={"","one","two","three","four","five","six","seven","eight","nine"};
for(;a&lt;=b;a++)
{
if(a&lt;=9)
cout &lt;&lt; name[a] &lt;&lt;"\n";
if(a&gt;9)
{
for(;a&lt;=b;a++)
{
if(a%2==0)
cout &lt;&lt; "even\n" ;
if(a%2==1)
cout &lt;&lt; "odd\n";
}
}
}

}
}

return 0;
}
```

Disclaimer: The above problem (For Loops in C++) is generated by Hackerrank but the solution is generated by CodingBroz.