For Loop in C++ | HackerRank Solution

Today we will be solving For Loop in C++ Hackerrank Problem.

Objective

In this challenge, you will learn the usage of the for loop, which is a programming language statement which allows code to be executed until a terminal condition is met. They can even repeat forever if the terminal condition is never met.

The syntax for the for loop is:

for ( <expression_1> ; <expression_2> ; <expression_3> )
    <statement>

    expression_1 is used for initializing variables which are generally used for controlling the terminating flag for the loop.
    expression_2 is used to check for the terminating condition. If this evaluates to false, then the loop is terminated.
    expression_3 is generally used to update the flags/variables.

The following loop initializes i to 0, tests that i is less than 10, and increments i at every iteration. It will execute 10 times.

for(int i = 0; i < 10; i++) {
    ...
}

 To learn about Loops and for loops in c in more details and depth. Read this.

Task

For each integer n in the interval [a,b] (given as input) :

• If 1<=n<=9, then print the English representation of it in lowercase. That is “one” for 1, “two” for 2, and so on.
• Else if n>9 and it is an even number, then print “even”.
• Else if n>9 and it is an odd number, then print “odd”.

Input Format

The first line contains an integer, a.

The second line contains an integer, b.

Constraints

1<=a<=b<=10^6

Output Format

Print the appropriate English representation,even, or odd, based on the conditions described in the ‘task’ section.

Note: [a,b] = {x ∈ Z | a ≤ x ≤ b}

• Sample Input

8

11

• Sample Output

eight

nine

even

odd

SOLUTIONS – For Loop in C++

#include <iostream>
#include <cstdio>
using namespace std;

int main() {
    // Complete the code.
     int a,b;
    cin >> a >> b;
    for(int i = a ; i<=b ; i++)
    {
        if((a>=1 && a<=9))
        {
            string name[10]={"","one","two","three","four","five","six","seven","eight","nine"};
            for(;a<=b;a++)
            {
                if(a<=9)
             cout << name[a] <<"\n";
             if(a>9)
        {
            for(;a<=b;a++)
            {
                if(a%2==0)
             cout << "even\n" ;
               if(a%2==1)
              cout << "odd\n";
            }
            }
        }
        
        }
    }
    
    return 0;
}

Disclaimer: The above problem (For Loops in C++) is generated by Hackerrank but the solution is generated by CodingBroz.