Find two numbers which adds to the target number in a given sorted array – Java

Given an array of integers numbers that is already sorted in ascending order, find two numbers such that they add up to a specific target number.

Return the indices of the two numbers (1-indexed) as an integer array answer of size 2, where 1 <= answer[0] < answer[1] <= numbers.length.

You may assume that each input would have exactly one solution and you may not use the same element twice.

Example 1:

Input: numbers = [2,7,11,15], target = 9
Output: [1,2]
Explanation: The sum of 2 and 7 is 9. Therefore index1 = 1, index2 = 2.

Example 2:

Input: numbers = [2,3,4], target = 6
Output: [1,3]

Example 3:

Input: numbers = [-1,0], target = -1
Output: [1,2]

Solution in Java :

class Solution {
    public int[] twoSum(int[] numbers, int target) {
        int i = 0, j = numbers.length - 1;
    while (i < j) {
      int x = (numbers[i] + numbers[j]);
      if (x == target) {
        int[] result = new int[2];
        result[0] = i + 1;
        result[1] = j + 1;
        return result;
      } else if (x < target) i++;
      else j--;
    }
    return new int[2];
    }
}

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