XML 1 – Find the Score in Python | HackerRank Solution

Hello coders, today we are going to solve XML 1 – Find the Score HackerRank Solution in Python.

XML 1 - Find the Score

Contents

Task

You are given a valid XML document, and you have to print its score. The score is calculated by the sum of the score of each element. For any element, the score is equal to the number of attributes it has.

Input Format

The first line contains N, the number of lines in the XML document.
The next N lines follow containing the XML document.

Output Format

Output a single line, the integer score of the given XML document.

Sample Input

6
<feed xml:lang='en'>
    <title>HackerRank</title>
    <subtitle lang='en'>Programming challenges</subtitle>
    <link rel='alternate' type='text/html' href='http://hackerrank.com/'/>
    <updated>2013-12-25T12:00:00</updated>
</feed>

Sample Output

5

Explanation

The feed and subtitle tag have one attribute each – lang.
The title and updated tags have no attributes.
The link tag has three attributes – rel, type and href.

So, the total score is 1 + 1 + 3 = 5.

There may be any level of nesting in the XML document.

NOTE: In order to parse and generate an XML element tree, use the following code:

>> import xml.etree.ElementTree as etree
>> tree = etree.ElementTree(etree.fromstring(xml))

Here, XML is the variable containing the string.
Also, to find the number of keys in a dictionary, use the len function:

>> dicti = {'0': 'This is zero', '1': 'This is one'}
>> print (len(dicti))

2


Solution – XML 1 – Find the Score in Python

import sys
import xml.etree.ElementTree as etree

def get_attr_number(node):
    # your code goes here
    return len(node.attrib) + sum(get_attr_number(child) for child in node);


if __name__ == '__main__':
    sys.stdin.readline()
    xml = sys.stdin.read()
    tree = etree.ElementTree(etree.fromstring(xml))
    root = tree.getroot()
    print(get_attr_number(root))

Disclaimer: The above Problem (XML 1 – Find the Score) is generated by Hacker Rank but the Solution is Provided by CodingBroz. This tutorial is only for Educational and Learning Purpose.

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