Eye and Identity in Python | HackerRank Solution

Hello coders, today we are going to solve Eye and Identity HackerRank Solution in Python.

Objective

identity

The identity tool returns an identity array. An identity array is a square matrix with all the main diagonal elements as 1 and the rest as 0. The default type of elements is float.

import numpy
print numpy.identity(3) #3 is for  dimension 3 X 3

#Output
[[ 1.  0.  0.]
 [ 0.  1.  0.]
 [ 0.  0.  1.]]

eye

The eye tool returns a 2-D array with 1‘s as the diagonal and 0‘s elsewhere. The diagonal can be main, upper or lower depending on the optional parameter k. A positive k is for the upper diagonal, a negative k is for the lower, and a 0 k (default) is for the main diagonal.

import numpy
print numpy.eye(8, 7, k = 1)    # 8 X 7 Dimensional array with first upper diagonal 1.

#Output
[[ 0.  1.  0.  0.  0.  0.  0.]
 [ 0.  0.  1.  0.  0.  0.  0.]
 [ 0.  0.  0.  1.  0.  0.  0.]
 [ 0.  0.  0.  0.  1.  0.  0.]
 [ 0.  0.  0.  0.  0.  1.  0.]
 [ 0.  0.  0.  0.  0.  0.  1.]
 [ 0.  0.  0.  0.  0.  0.  0.]
 [ 0.  0.  0.  0.  0.  0.  0.]]

print numpy.eye(8, 7, k = -2)   # 8 X 7 Dimensional array with second lower diagonal 1.

Task

Your task is to print an array of size N X M with its main diagonal elements as 1‘s and 0‘s everywhere else.

Note

In order to get alignment correct, please insert the line numpy.set_printoptions(legacy=”1.13″) below the numpy import.

Input Format

A single line containing the space separated values of N and M.
N denotes the rows.
M denotes the columns.

Output Format

Print the desired N X M array.

Sample Input

3 3

Sample Output

[[ 1.  0.  0.]
 [ 0.  1.  0.]
 [ 0.  0.  1.]]

Solution – Eye and Identity in Python

import numpy
print(str(numpy.eye(*map(int,input().split()))).replace('1',' 1').replace('0',' 0'))

Disclaimer: The above Problem (Eye and Identity) is generated by Hacker Rank but the Solution is Provided by CodingBroz. This tutorial is only for Educational and Learning Purpose.