# Digit Frequency in C | HackerRank Solution

Hey coderz, today we will be solving Digit Frequency in C HackerRank Solution.

Contents

## Objective

Given a string, s, consisting of alphabets and digits, find the frequency of each digit in the given string.

## Input Format

The first line contains a string, num which is the given number.

## Constraints

1 <= len(num) <= 1000

All the elements of num are made of english alphabets and digits.

## Output Format

Print ten space-separated integers in a single line denoting the frequency of each digit from 0 to 9.

Sample Input 0

``a11472o5t6``

Sample Output 0

``0 2 1 0 1 1 1 1 0 0 ``

Explanation 0

In the given string:

• 1 occurs two times.
• 2,4,5,6 and 7 occur one time each.
• The remaining digits 0, 3, 8 and 9 don’t occur at all.

Sample Input 1

``````lw4n88j12n1
``````

Sample Output 1

``````0 2 1 0 1 0 0 0 2 0
``````

Sample Input 2

``````1v88886l256338ar0ekk
``````

Sample Output 2

``1 1 1 2 0 1 2 0 5 0 ``

## Solution – Digit Frequency in C HackerRank Solution

```#include <stdio.h>
#include <string.h>
#include <math.h>
#include <stdlib.h>

int main() {
char s;
int i,a[] ={0,0,0,0,0,0,0,0,0,0};
while(scanf("%c", &s) == 1)
if(s >= '0' && s <= '9')
a[s-'0']+=1;

for(i=0;i<10;i++)
printf("%d ",a[i]);
return 0;
}
```

## EXPLANATION

• Declare an frequency array, arr of size 10 and initialize it with zeros, which will be used to count the frequencies of each of the digits occurring.
• Given a string, s, iterate through each of the characters in the string. Check if the current character is a number or not.
• If the current character is a number, increase the frequency of that position in the arr array by 1.
• Once done with the iteration over the string, s, in a new line print all the 10 frequencies starting from 0 to 9, separated by spaces.

Disclaimer: The above Problem (Digit Frequency in C) is generated by Hacker Rank but the Solution is provided by CodingBroz.

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