# Day 7: Regular Expressions III | 10 Days Of JavaScript | HackerRank Solution

Hello coders, today we are going to solve Day 7: Regular Expressions III HackerRank Solution which is a part of 10 Days of JavaScript Series.

Complete the function in the editor below by returning a RegExp object, re, that matches every integer in some string s.

## Constraints

• The length of string s is =>3 .
• It’s guaranteed that string s contains at least one integer.

## Output Format

The function must return a RegExp object that matches every integer in some string s.

Sample Input 0

`102, 1948948 and 1.3 and 4.5`

Sample Output 0

```102
1948948
1
3
4
5```

Explanation 0

When we call match on string s and pass the correct RegExp as our argument, it returns the following array of results: `[ '102', '1948948', '1', '3', '4', '5' ]`.

Sample Input 1

`1 2 3`

Sample Output 1

```1
2
3```

Explanation 1

When we call match on string s and pass the correct RegExp as our argument, it returns the following array of results: `[ '1', '2', '3' ]`.

## Solution – Day 7: Regular Expressions III

```'use strict';

process.stdin.resume();
process.stdin.setEncoding('utf-8');

let inputString = '';
let currentLine = 0;

process.stdin.on('data', inputStdin => {
inputString += inputStdin;
});

process.stdin.on('end', _ => {
inputString = inputString.trim().split('\n').map(string => {
return string.trim();
});

main();
});

return inputString[currentLine++];
}

function regexVar() {
/*
* Declare a RegExp object variable named 're'
* It must match ALL occurrences of numbers in a string.
*/
let re = /\d+/g;
/*
* Do not remove the return statement
*/
return re;
}

function main() {
const re = regexVar();