C++ Program to Find Smallest of N Numbers

In this post, we will learn how to find the smallest of N numbers using C++ Programming language.

This program takes an array as input and prints the smallest element of the array using for loop statement.

So, without further ado, let’s begin this tutorial.

C++ Program to Find Smallest of N Numbers

// C++ Program to Find Smallest of N Numbers
#include <iostream>
using namespace std;

int main(){
    int arr[10], count, i, min;
    
    // Asking for input
    cout << "Enter the size of the array: ";
    cin >> count;
    cout << "Enter the elements of the array: \n";
    for (i = 0; i < count; i++){
        cin >> arr[i];
    }
    min = arr[0];
    for (i = 0; i < count; i++){
        if (arr[i] < min){
            min = arr[i];
        }
    }
    cout << "Smallest Element: " << min;
    return 0;
}

Output

Enter the size of the array: 5
Enter the elements of the array: 
12
17
5
21
9
Smallest Element: 5

How Does This Program Work ?

    int arr[10], count, i, min;

In this program, we have declared some variables named count, i and min.

    // Asking for input
    cout << "Enter the size of the array: ";
    cin >> count;
    cout << "Enter the elements of the array: \n";
    for (i = 0; i < count; i++){
        cin >> arr[i];
    }

Then, the user is asked to enter the size of the array and the elements of the array.

    for (i = 0; i < count; i++){
        if (arr[i] < min){
            min = arr[i];
        }
    }

We calculate the smallest numbers of the array using for loop statement.

    cout << "Smallest Element: " << min;

Finally, the smallest element of the array which is stored in min named variable is displayed on the screen using cout statement.

Conclusion

I hope after going through this post, you understand how to find the smallest element in an array using C++ Programming language.

If you have any doubt regarding the program, feel free to contact us in the comment section. We will be delighted to help you.

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