Hello coders, today we are going to solve **Collections.Counter() in Python Hacker Rank Solution**.

**Objective**

A counter is a container that stores elements as dictionary keys, and their counts are stored as dictionary values.

**Sample Code **

>>> from collections import Counter >>> >>> myList = [1,1,2,3,4,5,3,2,3,4,2,1,2,3] >>> print Counter(myList) Counter({2: 4, 3: 4, 1: 3, 4: 2, 5: 1}) >>> >>> print Counter(myList).items() [(1, 3), (2, 4), (3, 4), (4, 2), (5, 1)] >>> >>> print Counter(myList).keys() [1, 2, 3, 4, 5] >>> >>> print Counter(myList).values() [3, 4, 4, 2, 1]

**Task**

** Raghu** is a shoe shop owner. His shop has

**X**number of shoes.

He has a list containing the size of each shoe he has in his shop.

There are ** N** number of customers who are willing to pay

**amount of money only if they get the shoe of their desired size.**

*x*iYour task is to compute how much money ** Raghu** earned.

**Input Format**

The first line contains **X**, the number of shoes.

The second line contains the space separated list of all the shoe sizes in the shop.

The third line contains **N**, the number of customers.

The next **N** lines contain the space separated values of the **shoe size** desired by the customer and **xi**, the price of the shoe.

**Constraints**

**0 < X < 10^3****0 < N <= 10^3****20 < xi < 100****2 < shoe size < 20**

**Output Format**

Print the amount of money earned by * Raghu*.

**Sample Input**

10 2 3 4 5 6 8 7 6 5 18 6 6 55 6 45 6 55 4 40 18 60 10 50

**Sample Output **

200

**Explanation **

**Customer 1:** Purchased size 6 shoe for **$55**.

**Customer 2:** Purchased size 6 shoe for** $45**.

**Customer 3:** Size 6 no longer available, so no purchase.

**Customer 4:** Purchased size 4 shoe for **$40**.

**Customer 5:** Purchased size 18 shoe for **$60**.

**Customer 6:** Size 10 not available, so no purchase.

Total money earned = **55 + 45 + 40 + 60** = **$200**

**Solution – Collections.Counter() Hacker Rank Solution in Python **

**Python 3**

# Enter your code here. Read input from STDIN. Print output to STDOUT from collections import Counter numShoes = int(input()) shoes = Counter(map(int, input().split())) numCust = int(input()) income = 0 for i in range(numCust): size, price = map(int, input().split()) if shoes[size]: income += price shoes[size] -= 1 print(income)

**Disclaimer:** The above Problem **(Collections.Counter() in Python)** is generated by **Hacker Rank** but the Solution is provided by **CodingBroz**.