Hello coders, today we are going to solve Breaking The Records HackerRank Solution which is a Part of HackerRank Algorithm Series.
Task
Maria plays college basketball and wants to go pro. Each season she maintains a record of her play. She tabulates the number of times she breaks her season record for most points and least points in a game. Points scored in the first game establish her record for the season, and she begins counting from there.
Example
scores = [12, 24, 10, 24]
Scores are in the same order as the games played. She tabulates her results as follows:
Count
Game Score Minimum Maximum Min Max
0 12 12 12 0 0
1 24 12 24 0 1
2 10 10 24 1 1
3 24 10 24 1 1
Given the scores for a season, determine the number of times Maria breaks her records for most and least points scored during the season.
Function Description
Complete the breakingRecords function in the editor below.
breakingRecords has the following parameter(s):
- int scores[n]: points scored per game
Returns
- int[2]: An array with the numbers of times she broke her records. Index 0 is for breaking most points records, and index 1 is for breaking least points records.
Input Format
The first line contains an integer n, the number of games.
The second line contains n space-separated integers describing the respective values of score0, score1, . . . , scoren – 1.
Constraints
- 1 <= n <= 1000
- 0 <= scores[i] <= 108
Sample Input 0
9
10 5 20 20 4 5 2 25 1
Sample Output 0
2 4
Explanation 0
The diagram below depicts the number of times Maria broke her best and worst records throughout the season:
She broke her best record twice (after games 2 and 7) and her worst record four times (after games 1, 4, 6, and 8), so we print 2 4
as our answer. Note that she did not break her record for best score during game 3, as her score during that game was not strictly greater than her best record at the time.
Sample Input 1
10
3 4 21 36 10 28 35 5 24 42
Sample Output 1
4 0
Explanation 1
The diagram below depicts the number of times Maria broke her best and worst records throughout the season:
She broke her best record four times (after games 1, 2, 3, and 9) and her worst record zero times (no score during the season was lower than the one she earned during her first game), so we print 4 0
as our answer.
Solution – Breaking The Records
C++
#include<bits/stdc++.h> using namespace std; #define ll long long #define lim 10000007 #define pb push_back #define S second #define pb push_back #define mp make_pair #define INF 1e18 #define fr(i,j,k) for(ll i=j;i<=k;i++) #define frd(i,j,k) for(ll i=j;i>=k;i--) #define F first #define sd(n) scanf("%lld",&n) #define pd(n) printf("%lld\n",n) #define db double #define mod 1000000007 #define pii pair<ll,ll> int main() { ll n; cin>>n; ll mx; cin>>mx; ll mn=mx; ll a1=0,a2=0; n--; ll x; while(n--) { cin>>x; if(x>mx) a1++; if(x<mn) a2++; mx=max(mx,x); mn=min(mn,x); } cout<<a1<<" "<<a2<<endl; }
Python
input() a = list(map(int, input().split())) m = M = a[0] x = y = 0 for i in a[1:]: if i > M: M = i x += 1 elif i < m: m = i y += 1 print(x, y)
Java
import java.io.*; import java.util.*; import java.text.*; import java.math.*; import java.util.regex.*; public class Solution { public static void main(String[] args) { Scanner in = new Scanner(System.in); int n = in.nextInt(); int[] score = new int[n]; for(int score_i=0; score_i < n; score_i++){ score[score_i] = in.nextInt(); } // your code goes here int most = score[0]; int least = score[0]; int mr = 0; int lr = 0; for( int i = 1; i < n; i++ ){ if( score[i] > most ){ mr++; most = score[i]; } if( score[i] < least ){ lr++; least = score[i]; } } System.out.print(mr + " " + lr); } }
Disclaimer: The above Problem (Breaking The Records) is generated by Hacker Rank but the Solution is Provided by CodingBroz. This tutorial is only for Educational and Learning Purpose.